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3 years ago

What is the answer to this math problem??

Mathematics

1 answer:

lakkis [162]3 years ago

4 0

Answer:

Step-by-step explanation:

given $\frac{1}{49^2}$

note that 49² = 2401, hence

$\frac{1}{49^2}$ = $\frac{1}{2401}$ → A

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Express the perimeter of one side of the square using s

r-ruslan [8.4K]

s is the length and w is width which the equation is 2s+2w=P

8 0

3 years ago

Find all values of x in the interval [0, 2π] that satisfy the equation. <br><br>6sin²(x) = 3

34kurt

Answer:

The solutions are π/4, 3π/4,5π/4,7π/4

Step-by-step explanation:

The given equation is

6sin²(x) = 3

Divide by 6 to get:

${ \sin}^{2} (x) = \frac{1}{2}$

This implies that;

$\sin(x) = \pm \frac{ \sqrt{2} }{2}$

$\sin(x) = \frac{ \sqrt{2} }{2}$

$x = \frac{\pi}{4}$

in the first quadrant

$x = \frac{3\pi}{4}$

in the second quadrant.

$\sin(x) = - \frac{ \sqrt{2} }{2}$

$x = \frac{5\pi}{4}$

in the third quadrant

$x = \frac{7\pi}{4}$

5 0

3 years ago

When rewriting y = 2x + 1 in function notation, what do you replace with f(x)?

zmey [24]

You replace the y with f(x)
So it becomes f(x)=2x+1

6 0

3 years ago

Read 2 more answers

4. Suppose that you have an enormous grapefruit that is 92% water (by weight). The grapefruit weights 100 pounds. If the water c

Anton [14]

Answer:

80 pounds.

Step-by-step explanation:

Let W₁ be the initial weight of water in the grapefruit, W₂ be the weight of water in the grapefruit after evaporation, and M be the total weight of the grapefruit after evaporation. Assuming that, originally, the grapefruit weighed 100 pounds with a 92% water content and the weight of the "non-water" part of the fruit (100 - W₁) does not change. The final weight of the grapefruit (M) is given by:

$W_1=0.92*100=92\\W_2=0.90*M\\W_2+(100-W_1) = M\\W_2=M-8\\(1-0.9)M=8\\M=80$

The grapefruit now weighs 80 pounds.

8 0

3 years ago

For what value of x is line m parallel to line n? This is quite urgent.

pishuonlain [190]

Answer:

Step-by-step explanation:

Line m and n are parallel lines cut by the transversal (without name). So, angles with measures $65^{\circ}$ and $(3x+5)^{\circ}$ are corresponding angles.

The Corresponding Angles Theorem states if two parallel lines are cut by a transversal, then the pairs of corresponding angles are congruent.

Hence,

$3x+5=65\\ \\3x+5-5=65-5\\ \\3x=60\\ \\x=\dfrac{60}{3}\\ \\x=20$

6 0

3 years ago