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3 years ago

Why might a person who has skin cancer later develop a tumour on her lungs?

2 answers:

5 0

Results showed that people with nonmelanoma skin cancer were at an increased risk of developing the deadly skin cancer melanoma, and that women with nonmelanoma skin cancer were at increased risk of lung cancer and breast cancer, according to the study. Common sites for metastases include the lymph nodes, lungs, liver, bones and brain. Melanoma tumors that have metastasized to other parts of the body are still considered melanoma. For example, melanoma found in the lungs is called metastatic melanoma of the lung or melanoma with lung metastases. Skin cancer is the out-of-control growth of abnormal cells in the epidermis, the outermost skin layer, caused by unrepaired DNA damage that triggers mutations. These mutations lead the skin cells to multiply rapidly and form malignant tumors. Hope this helps!

alina1380 [7]3 years ago

3 0

Answer: The cancer of the skin metastasizes into the lymph joints (spreads), and they run everywhere in the body, dropping bad cells when they go. the lungs are super vascular (carry a lot of blood flow), and so is the organ. Therefore, they are favorite places for the cancer cells to end up and grow.

Explanation: hoped this helped:)) you can just search it up

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9. If you could choose one ecosystem to spend the afternoon, would you choose the beach, the mountains, grasslands, or desert? W

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I would choose the mountain ecosystem.

The mountain ecosystem contains a complex living organisms. Mountain lands support a diverse array of habitats with large range of plants and animals. It is very crucial for biological diversity and is very wonderful to see. The climate is mostly cool which is fitting for relaxation.

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3 years ago

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Current studies on frogs and wildlife indicate that hormonally active agents (HAAs) are __________.

Anastaziya [24]

Answer:

Explanation:

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3 years ago

Which lists the correct order of evolutionary history?

Mama L [17]

The lists of the correct order of evolutionary history is Jellyfish, Reptiles, Mammals. This three are classified as vertebrates and all I know that almost all the animals we know are vertebrates. Jellyfish is a fish that do not have a backbones, example of reptiles is garter snake, there are so many mammals in the forest such as bat, rodent, bear and much more.

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3 years ago

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Why would life be impossible without enzymes?

Cloud [144]

All the important functions of our body would simply be too slow for us to survive such as digestion. if we didn't digest quick enough our stomachs would be bloated all the time

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3 years ago

Mars had an orbital period of 1.88 years. In two or more complete sentences,explain how to calculate the average distance from m

Vanyuwa [196]

This is an interesting problem involving astronomy, in fact, simple physics.
Let r=distance of sun to mars, in metres

Mars had an orbital period of 1.88 years.
=>
tangential velocity, v, of the planet, in m/s is
$v=\frac{2\pi{r}}{T}$
 $=\frac{2\pi{r}}{1.88*365.25*86400}$ m/s, accounting for leap years
$=3.371*10^{-8}\pi{r}$ m/s

The centripetal force, Fc, generated is
$Fc=\frac{mv^2}{r}$
where m=mass of mars = 6.39*10^(24) kg
$=\frac{mv^2}{r}$
$=\frac{6.39*10^{24}v^2}{r}$
$=7.26168*10^9\pi^2r$

The gravitation pull from the sun, Fg, is given by
$Fg=\frac{GMm}{r^2}$
where G=grav. const., =6.67408*10^(-11) m^3 kg^(-1) s^(-2)
M=mass of sun=1.989*10^(30) kg
$=\frac{6.67408*10^{-11}1.989*10^{30}6.39*10^{24}}{r^2}$
$=\frac{8.4826*10^44}{r^2}$

Since the radial distance is in equilibrium, the average distance, r can be found by equation Fc=Fg and solving for r:
Fc=Fg
=>
$7.26168*10^9\pi^2r=\frac{8.4826*10^44}{r^2}$
Solving for the real root:
$r^3=\frac{8.48256*10^44}{7.26168*10^9*%pi^2}$
$=\frac{1.1681263*10^{35}}{\pi^2}$
=2.279*10^11 m

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3 years ago