2 years ago

Can someone help me please

Mathematics

1 answer:

lora16 [44]2 years ago

3 0

Answer:

when Sarah makes 8 batches she will have 300 cookies

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Find the value of k and x2<br> x^2+ 13x + k = 0, x1=-9

Anarel [89]

Given:

The quadratic equation is:

$x^2+13x+k=0$

$x_1=-9$

To find:

The value of k and $x_1$ .

Solution:

We have,

$x^2+13x+k=0$ ...(i)

Putting $x=-9$ , we get

$(-9)^2+13(-9)+k=0$

$81-117+k=0$

$-36+k=0$

$k=36$

Putting $k=36$ in (i), we get

$x^2+13x+36=0$

Splitting the middle term, we get

$x^2+9x+4x+36=0$

$x(x+9)+4(x+9)=0$

$(x+9)(x+4)=0$

$x=-9,-4$

Here, $x_1=-9$ and $x_2=-4$ .

Therefore, the required values are $k=36$ and $x_2=-4$ .

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3 years ago

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ycow [4]

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Step-by-step explanation: Sum is adding.

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Xy+(4(20))>x-5y(2+9-7)

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