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3 years ago

Xy+(4(20))>x-5y(2+9-7)

Mathematics

1 answer:

prohojiy [21]3 years ago

3 0

I'll solve for y xy+(4(20))>x-5y(2+9-7)

xy+4(20)>x-5y(2+9-7)

xy+4(20)>x-5y(4)

xy+4(20)>x-20y

xy+80>x-20y

xy+20y+80>x

y(x+20)>-80+x

y>(-80+x)/(x+20)

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does anyone know how to solve this? i dont remember doing any problems in class related to this and this single question alone h

Serggg [28]

Answer:

The answer to your question is below

Step-by-step explanation:

Process

1.- Get two points of each line to find the equation of each line

Continuous line A (-10, 0) B (0, 9)

Dotted line C (-2, -3) D (0, -10)

Slope continuous line m = $\frac{9 - 0}{0 + 10} = = \frac{9}{10}$

Slope dotted line m = $\frac{-10 + 3}{0 + 2} = \frac{-7}{2}$

2.- Get the equation of each line

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Dotted line y + 3 = -7/2(x + 2)

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y = -7/2x -7 - 3

y = -7/2x - 10

3.- Find the inequalities

Continuous line (we need the upper area of the line, we use ≥)

y ≥ 9/10x + 9

The Dotted line (we also need the upper area, we use >)

y > -7/2x - 10

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