A catapult launches a boulder with an upward velocity of 184 feet per second. The height of the boulder, h, in feet after t seco
2 answers:
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Answer: a) -13.25 N, b) 1.78 m/sec
Step-by-step explanation:
Since we have given that
where
As we know that
Here, x= 0.5 m
So, it becomes,
Now, we need to find the velocity when it crosses the origin,
Hence, a) -13.25 N, b) 1.78 m/sec
