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disa [49]
2 years ago
8

Blake and two friends equally shared the cups of water shown in the picture.

Mathematics
1 answer:
3241004551 [841]2 years ago
6 0
The answer would be c- 2/6

there are six cups total and three (blake plus two others) friends

there are two ways you can solve this…

1. by making groups
if you look at the picture, you can split it into three groups because that is the number of people, then count how many cups there are in one group which will be your numerator for the denominator six which is the total

2. simple division
divide the total number of cups buy the number of people which is 3
you get two and follow the same process above

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a school counts the number of students taking AMDM and find 221 students taking AMDM. they also count the number of students tak
Masja [62]

Answer:

33.195%

Step-by-step explanation:

AMDM: 221 students

Physics: 241 students

Taking both: 80 students

80/241 = ~33.195%

4 0
3 years ago
Use stoke's theorem to evaluate∬m(∇×f)⋅ds where m is the hemisphere x^2+y^2+z^2=9, x≥0, with the normal in the direction of the
ludmilkaskok [199]
By Stokes' theorem,

\displaystyle\int_{\partial\mathcal M}\mathbf f\cdot\mathrm d\mathbf r=\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S

where \mathcal C is the circular boundary of the hemisphere \mathcal M in the y-z plane. We can parameterize the boundary via the "standard" choice of polar coordinates, setting

\mathbf r(t)=\langle 0,3\cos t,3\sin t\rangle

where 0\le t\le2\pi. Then the line integral is

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=2\pi}\mathbf f(x(t),y(t),z(t))\cdot\dfrac{\mathrm d}{\mathrm dt}\langle x(t),y(t),z(t)\rangle\,\mathrm dt
=\displaystyle\int_0^{2\pi}\langle0,0,3\cos t\rangle\cdot\langle0,-3\sin t,3\cos t\rangle\,\mathrm dt=9\int_0^{2\pi}\cos^2t\,\mathrm dt=9\pi

We can check this result by evaluating the equivalent surface integral. We have

\nabla\times\mathbf f=\langle1,0,0\rangle

and we can parameterize \mathcal M by

\mathbf s(u,v)=\langle3\cos v,3\cos u\sin v,3\sin u\sin v\rangle

so that

\mathrm d\mathbf S=(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv=\langle9\cos v\sin v,9\cos u\sin^2v,9\sin u\sin^2v\rangle\,\mathrm du\,\mathrm dv

where 0\le v\le\dfrac\pi2 and 0\le u\le2\pi. Then,

\displaystyle\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S=\int_{v=0}^{v=\pi/2}\int_{u=0}^{u=2\pi}9\cos v\sin v\,\mathrm du\,\mathrm dv=9\pi

as expected.
7 0
3 years ago
??????????????????????????
Umnica [9.8K]

Solution:

<em>Simple Interest = Principal Amount × Rate of Interest/100 × Time</em>

Here, Principal Amount = $6000

Rate of Interest =  6%

Time = 4 years

Simple Interest = 6000 × 6/100 × 4 = <em>$1440</em>

3 0
2 years ago
If g(x) = 10 - 2x then which of the following is the value of g(7)?
slega [8]

Answer:

g(7)= -4

Step-by-step explanation:

10-2(7)

10-14

=-4

4 0
2 years ago
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Fittoniya [83]

Answer:

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Step-by-step explanation:

Base x Height

So 9 x 20 to get 180

3 0
2 years ago
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