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zavuch27 [327]
3 years ago
9

What is the surface area of the triangular prism shown

Mathematics
1 answer:
Goryan [66]3 years ago
7 0

Answer:

108 cm^2

Step-by-step explanation:

SA = PH + 2 * 1/2bh

SA = (3 + 4 + 5)(8) + 2 * (1/2) * 3 * 4

SA = 96 + 12

SA = 108

Answer: 108 cm^2

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I need help please!!!!
ycow [4]

Answer:

x = 14.48

Step-by-step explanation:

first we have to see that we have the measurements from all sides

and we know that the angle between side 21 and 20 is 90 degrees

well to start we have to know the relationships between angles, legs and the hypotenuse.

a: adjacent

o: opposite

h: hypotenuse

sin α = o/h

cos α= a/h

tan α = o/a

let's take the left angle as α

sin α = 21/29

α = sin^-1 (21/29)

α = sin^-1 (0.7241)  

α = 46.397

Now we do the same with the smaller triangle

tan α = o/a

sin 46.397  = x/20

0.724 = x/20

0.724 * 20 = x

14.48 = x

x = 14.48

if we want to check it we can do the same procedure with the other angle

4 0
4 years ago
If an=5n-3 find the common difference​
elena55 [62]

Answer:

Hi here is your answer

an=5n-3

an-1= -3+5n

an-1= -3+5(n-1)

an-1= -3+5n-5

an-1= 5n-7

d= an- an-1

d=(5n-3)-(5n-7)

d=5n-3-5n+7

d=4

Answer: d = 4

Hope this helps you.

3 0
4 years ago
Read 2 more answers
P (6,6) y=2/3x
matrenka [14]

Answer:

y = -\frac{3}{2}x+15

Step-by-step explanation:

Given:

Given point P(6, 6)

The equation of the line.

y = \frac{2}{3}x

We need to find the equation of the line perpendicular to the given line that contains P

Solution:

The equation of the line.

y = \frac{2}{3}x

Now, we compare the given equation by standard form y = mx +c

So, slope of the line m_{1} = \frac{2}{3}, and

y-intercept c=0

We know that the slope of the perpendicular line m_{1}\times m_{2}  = -1

m_{2}=-\frac{1}{m_{1}}

m_{2}=-\frac{1}{\frac{2}{3} }

m_{2}=-\frac{3}{2}

So, the slope of the perpendicular line m_{2}=-\frac{3}{2}

From the above statement, line passes through the point P(6, 6).

Using slope intercept formula to know y-intercept.

y=mx+c

Substitute point P(x_{1}, y_{1})=P(6, 6) and m = m_{2}=-\frac{3}{2}

6=-\frac{3}{2}\times 6 +c

6=-3\times 3 +c

c=6+9

c=15

So, the y-intercept of the perpendicular line c=15

Using point slope formula.

y=mx+c

Substitute m = m_{2}=-\frac{3}{2} and c=15 in above equation.

y = -\frac{3}{2}x+15

Therefore: the equation of the perpendicular line y = -\frac{3}{2}x+15

8 0
4 years ago
4-7x=1-6x <br><br> Please explain why the answer is the answer and I’ll give brainlist
Mrac [35]

Answer:

3

Step-by-step explanation:

5 0
3 years ago
The question is in the picture. will give brainilist.​
sergeinik [125]
Value of y = 30 and value of x = 30.3
3 0
3 years ago
Read 2 more answers
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