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strojnjashka [21]

3 years ago

15

Find the values for x so that the perimeter of this rectangle is no greater than 60 centimeters. 25 cm x cm Find the allowed val

ues for x. Do not type any units.

1 answer:

tekilochka [14]3 years ago

6 0

Answer:

To find the values for <em>x </em>so that the perimeter of the rectangle is not greater than <em>60 cm</em>, includes <em>25 cm </em>on <em>one side</em>, we have already found the first half of this answer.

The <em>only </em>way to make this <u><</u> 60 is to have the parallel sides (depending on which side is 25,) is <em>5 cm.</em> That way, it will be exactly <em>60 cm</em>, meaning we have reached our goal of <u><</u> 60 cm.

This is the best I can do at the moment.

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natta225 [31]

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7 0

3 years ago

m∠1 is 4 times m∠2. ∠1 and ∠2 are complementary. ∠1 and ∠3 are vertical angles. ∠3 and ∠4 are supplementary. What are the measur

kherson [118]

Answer:

Step-by-step explanation:

Let's write a system of equations. I'm going to call them w, x, y, and z.

w = 4x (because m∠1 is 4 times m∠2)

w + x = 90 (bc ∠1 and ∠2 are complementary, meaning they add up to 90)

w = y (bc ∠1 and ∠3 are vertical angles, meaning they are equal)

y + z = 180 (bc ∠3 and ∠4 are supplementary, meaning they add up to 180)

When we substitute w=4x into the second equation, we get 5x=90 → m∠2 = 18°. Since w=4x, m∠1 = 18*4 = 72°. Since w=y, m∠3 = 18°. Finally, because y+z=180, m∠4 = 180-18 = 162°. Hope this helps!

3 0

3 years ago

Solve the equations for all values of x by completing the square x^2+62=-16x

lorasvet [3.4K]

Answer:

$x = \sqrt{2} - 8\\x = -\sqrt{2} - 8$

Step-by-step explanation:

To complete the square, we first have to get our equation into $ax^2 + bx = c$ form.

First we add 16x to both sides:

$x^2 + 16x + 62 = 0$

And now we subtract 62 from both sides.

$x^2 + 16x = -62$

We now have to add $(\frac{b}{2})^2$ to both sides of the equation. b is 16, so this value becomes $(16\div2)^2 = 8^2 = 64$ .

$x^2 + 16x + 64 = -62+64$

We can now write the left side of the equation as a perfect square. We know that x+8 will be the solution because $8\cdot8=64$ and $8+8=16$ .

$(x+8)^2 = -62 + 64$

We can now take the square root of both sides.

$x+8 = \sqrt{-62+64}\\\\ x+8 = \pm \sqrt{2}$

We can now isolate x on one side by subtracting 8 from both sides.

$x = \pm\sqrt{2} - 8$

So our solutions are

$x = \sqrt{2} - 8\\x = -\sqrt{2} - 8$

Hope this helped!

4 0

3 years ago

Find angle A and angle B..

ExtremeBDS [4]

Step-by-step explanation:

$\sf{\bold{\blue{\underline{\underline{Given}}}}}$

$\tt{\angle{c}=110°}$

and,

$\tt{BC=AC}$

⠀⠀⠀⠀

$\sf{\bold{\red{\underline{\underline{To\:Find}}}}}$

☆Find the $\angle{B} ~and~\angle{A}$

$\sf{\bold{\purple{\underline{\underline{Solution}}}}}$

Here,

BC =AC

so,

⠀⠀⠀

$\angle{A}=\angle{B}$

we know that,

$\tt{\boxed{\pink{\angle{A}+\angle{B}+\angle{C}=180°}}}$

But $\angle{C}=110°$ (Ģìvéñ)

so..

$\angle{A}+\angle{B}+110°=180°$

$\angle{A}+\angle{A}+110°=180°$

$\because{\angle{A}=\angle{B} }$

$2\angle{A}=180°-110°$

$2\angle{A}=70°$

$\angle{A}=\dfrac{70°}{2}$

$\boxed{\orange{\angle{A}=35°}}$

But...

$\angle{A}=\angle{B}$

soo,

$\boxed{\orange{\angle{B}=35°}}$

$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

⠀⠀⠀⠀

$\boxed{\green{\angle{A}=35°}}$

$\boxed{\green{\angle{B}=35°}}$

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3 years ago

Найдите высоту стола.

crimeas [40]

I'm not sure but I'm gonna guess that the answer is 50?

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3 years ago