Based on the given current and the given resistance, the voltage of the current is 14 + j8
<h3>How to determine the voltage of the current?</h3>
From the question, we have the following parameters
current of 4+j2 amps and a resistance of 2-j3 ohms.
This can be rewritten as:
Current (I) = 4+j2 amps
Resistance (R) = 2-j3 ohms.
The formula to calculate voltage is given as
Voltage=(current) × (resistance)
Rewrite as:
V = I * R
Substitute the known values in the above equation
V = (4 + j2) * (2 - j3)
Expand the brackets
V = 8 - j4 + j12 + 6
Collect the like ters
V = 8 + 6 - j4 + j12
Evaluate the like term
V = 14 + j8
Based on the given current and the given resistance, the voltage of the current is 14 + j8
Read more about current and voltage at:
brainly.com/question/14883923
#SPJ1
Hi :)
Let's remember some arithmetic w/ negative integers :
a+(-b)=a-b
a-(-b)=a-b
Now
8-(-9)=8+9=17
So the answer's 17
I hope this helps
Answer:
.32
Step-by-step explanation:
Answer:
8y^6z^6
Step-by-step explanation:
Reduce the numbers with greatest common divisor 4.
32y^2 x z/4 x y^4 z^5 = 8y^2 zy^4 z^5
Calculate the product.
8y^6z^6
