Answer:
x^2+y^2-32x+24y+375=0
Step-by-step explanation:
Equation of circle with given centre (h,k) and radius=r is
(x-h)^2+(y-k)^2=r^2
Given centre are=(16, - 12) and radius= 5
So equation of circle=
(x-16)^2+(y- -12)^2=5^2
x^2-32x+256+y^2+24y+144=25
x^2+y^2-32x+24y+375=0
Answer
7h+3s=27.95 subtract 7h from both sides
3s=27.95-7h divide both sides by 3
s=(27.95-7h)/3
Then we are told:
5h+4s=23.4, using s found above makes this equation become:
5h+4(27.95-7h)/3=23.4 multiply both sides by 3
15h+4(27.95-7h=70.2 perform indicated multiplication on left side
15h+111.8-28h=70.2 combine like terms on left side
-13h+111.8=70.2 subtract 111.8 from both sides
-13h=-41.6 divide both sides by -13
h=$3.20
2x+15x you can just switch the two.
Substitute 4 for y. Then -3x^2 + 16 = 52.
Solve for x. Subtract 16 from both sides, obtaining -3x^2 = 36.
Divide both sides by -3, obtaining x^2 = -12. This last result makes no sense, as no square of a real number could be negative. Probably this is where you're ":getting a negative answer."
If imaginary answers were allowed, then x = i*√12 = i*2√3 or x = -i*2√3.
x =
