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skad [1K]
3 years ago
13

How do I simplify this math problem -9c+9c-12

Mathematics
2 answers:
meriva3 years ago
7 0

Answer: Add -9c and 9c together which would lead to 0c which equals 0. So the simplified problem would be -12.

Step-by-step explanation:

steposvetlana [31]3 years ago
5 0

Answer:

c-12

Step-by-step explanation:

If there's -9 c's and plus 9 c's then they cancel each other out and become just c

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In a 45-45-90 triangle, the hypotenuse is 7, find both the legs
Nadya [2.5K]

Answer: If the hypotenuse is 7, the other 2 sides are \sqrt{24.5} 0r about = 4.95

Step-by-step explanation:  in a 45-45-90 triangle, the legs are equal.

a² + b² = c² .   2(a²) = 49  a² = 49/2

So find the square root of 24.5

\sqrt{24.5}   =4.949747468 .round to 4.95

7 0
3 years ago
The quadratic function d= -4x+1,100 models a snowboarder's distance, in feet, from the bottom of a hill x seconds after the snow
Fynjy0 [20]

Answer:

16 seconds (Approximately)

Step-by-step explanation:

Given:

The function that gives the distance of snowboarder from the bottom of hill with time 'x' is:

d=-4x^2+1100

Final position of the snowboarder is d=100\ ft

Now, plugging in 100 for 'd' and solving for 'x', we get:

100=-4x^2+1100

Adding -1100 both sides, we get:

100-1100=-4x^2+1100-1100\\-1000=-4x^2

Dividing both sides by -4, we get:

\frac{4x^2}{4}=\frac{1000}{4}\\x^2=250

Taking square root and neglecting the negative root as time can't be negative. So,

\sqrt{x^2}=\sqrt{250}\\x=5\sqrt{10}=15.8\ s\approx 16\ s

Therefore, after 16 seconds, the snowboarder will be at a distance of 100 ft from bottom of hill.

7 0
3 years ago
Consider trapezoid LMNO.
jenyasd209 [6]

The side LO is congruent to the side MN, the diagonal LN is congruent to the diagonal MO, and the angle L is congruent to the angle M in an isosceles trapezoid, denoted by the symbols LMNO.

What are the conditions for an Isosceles Trapezoid?

The conditions listed below demonstrate that any trapezoid is an isosceles trapezoid:

  • The length of both legs is the same.
  • 2nd condition: The base angles are of equal proportion.
  • The length of the diagonals is the same.

When these conditions are met by the given trapezoid LMNO, it will be referred to as an isosceles trapezoid. Hence, the following conditions of trapezoid LMNO need to be fulfilled,

LN ≅ MO

LO ≅ MN

∠L ≅ ∠M

Learn more about a trapezoid here:

brainly.com/question/26335898

#SPJ1

3 0
2 years ago
In the hyperbola graph,how do you find the domain and range?​
xxTIMURxx [149]

Step-by-step explanation:

<h2><em>y = ± 5⁄2 x</em></h2><h2><em>y = ± 5⁄2 xThe equation is the left half of the hyperbola. The domain is ( – ∞, – 1⁄5 ]. The range is ( – ∞, ∞ ). The vertical line test indicates that this is not the graph of a function.</em></h2>
3 0
3 years ago
HELP PLEASE <br><br>must show work ​
matrenka [14]

Answer:

1. 4n^3

2. 4k^7

3. 3

4. -30x

5. -6

Step-by-step explanation:

1. The prime factorization of 12 is 2 x 2 x 3 and the prime factorization of 16 is 2 x 2 x 2 x 2. When you look at these two expressions you can see the common factors of these two numbers are 2 x 2, which is 4. Next, we look at the GCF of the N's which would be n^3 since n^5 has three N's in it. Therefore, we get 4n^3 when we multiply the two together.

2. The factors of 8 are 1, 2, 4, and 8. Out of these, 1, 2, and 4 are the only factors that 20 shares with it and 4 is the greatest. Then, we look at the K's and the GCF of the K's is k^7 since k^8 has seven K's. We multiply the two and we get 4k^7.

3. Since one of the numbers of the three given here does not include the variable n, there will not be any N's in the GCF of the three, so we don't have to worry about that. Now, we just find the GCF of 18, -24, and -21. The factors of 18 are 1, 2, 3, 6, 9, and 18, the factors of 24 are 1, 2, 3, 4, 6, 8, 12, and 24, and lastly, the factors of 21 are 1, 3, 7, and 21. From these, 3 is the biggest common divisor, therefore the GCF is 3.

4. Between the two X's, X^1 is the biggest amount of X's this GCF has, so the final GCF will be some constant multiplies with X. Since we are dealing with bigger numbers on this problem, we should use prime factorization. The prime factorization of 90 is 2 x 3 x 3 x 5, and the prime factorization of 120 is 2 x 2 x 2 x 3 x 5. From these expressions, we take the biggest amount of each common factor as we can. Since these expressions both have 2, we take the smaller amount of 2's which is one two. Then we get one three from both expressions, and one five as well. 2 times 3 times 5 equals 30, therefore, we get -30x, and not 30x, because both of these numbers are negatives.

5. All of these numbers do not have an x, so there won't be an x in our GCF. Another method of quickly finding the GCF of numbers is to look at the smallest number's factors first to see what factors it shares with the other numbers. The factors of 12 are 1, 2, 3, 4, 6, and 12. 42 and 30 do not have the factor 12, so we can go down the list and see if 42 and 30 share the factor 6, which they do since 6 times 7 is 42 and 6 times 5 is 30. Since all of these numbers share the negative sign, the GCF of these three numbers is -6.  

5 0
3 years ago
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