<span>The answer is </span><span>201326592. The </span>decimal number that the bit pattern 0×0c000000 represent if it is a two's complement integer is 201326592.
Please Help! Unit 6: Lesson 1 - Coding Activity 2
Instructions: Hemachandra numbers (more commonly known as Fibonacci numbers) are found by starting with two numbers then finding the next number by adding the previous two numbers together. The most common starting numbers are 0 and 1 giving the numbers 0, 1, 1, 2, 3, 5...
The main method from this class contains code which is intended to fill an array of length 10 with these Hemachandra numbers, then print the value of the number in the array at the index entered by the user. For example if the user inputs 3 then the program should output 2, while if the user inputs 6 then the program should output 8. Debug this code so it works as intended.
The Code Given:
import java.util.Scanner;
public class U6_L1_Activity_Two{
public static void main(String[] args){
int[h] = new int[10];
0 = h[0];
1 = h[1];
h[2] = h[0] + h[1];
h[3] = h[1] + h[2];
h[4] = h[2] + h[3];
h[5] = h[3] + h[4];
h[6] = h[4] + h[5];
h[7] = h[5] + h[6];
h[8] = h[6] + h[7]
h[9] = h[7] + h[8];
h[10] = h[8] + h[9];
Scanner scan = new Scanner(System.in);
int i = scan.nextInt();
if (i >= 0 && i < 10)
System.out.println(h(i));
}
}
Answer:
Polymorphism
Explanation:
You can have a basic button class that gets inherited by other classes.
class Button {
function pushButton(){}
}
class ElevatorButton extends Button{};
class BigRedButton extends Button{};
With these new classes, they inherit from the basic button class. They can decide what happens when the method pushButton() is called.
You don't need to worry about what pushButton() actually does, you can just call it if the object is of the type "Button" and you can expect it to work.
Answer:
The program to this question can be defined as follows:
Program:
n = int(input("Enter the number: ")) #input value from user end
print("Entered value: ",n) #print value
lt = [] #defining an empty list
for i in range(n): # loop to input values
lt.append(int(input())) #add values in the list
minimum_value = min(lt) # finding minimum value
print("Smallest value: ",minimum_value) #print value
print("Normalising data: ") #print message
for x in lt: #defining loop normalising value
print(x-minimum_value) #print normalised values
Output:
Enter the number: 5
Entered value: 5
90
60
30
80
70
Smallest value: 30
Normalising data:
60
30
0
50
40
Explanation:
In the given code a variable "n" is defined, that input value from the user end, in the next step, an empty list is defined, an two for loop is declared, which calculates the given value.
- In the first for loop, the append method is used, that input values in the given list, and at the last use the min function, that prints the smallest value in the list, and stores its value in the "minimum_value".
- In the second for loop, the "minimum_value" variable value is subtracted from the list value and print its values.
Answer:
The function in Python is as follows:
def rotateRight(strng, d):
lent = len(strng)
retString = strng[lent - d : ] + strng[0 : lent - d]
return retString
Explanation:
This defines the function
def rotateRight(strng, d):
This calculates the length of the string
lent = len(strng)
This calculates the return string
retString = strng[lent - d : ] + strng[0 : lent - d]
This returns the return string
return retString
Addition:
The return string is calculated as thus:
This string is split from the <em>index passed to the function to the last element of the string, i.e. from dth to last.</em>
<em>The split string is then concatenated to the beginning of the remaining string</em>
