I need the measure of

Factor the following Polynomial a) 6x - 18

musickatia [10]

U could easily do this on Photo-math- but here: 6(x−3)

7 0

2 years ago

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Change 5 ft. to yards

Zielflug [23.3K]

5 feet = 1 2/3 yards

6 0

2 years ago

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An environment engineer measures the amount ( by weight) of particulate pollution in air samples ( of a certain volume ) collect

Serggg [28]

Answer:

$k = 1$

$P(x > 3y) = \frac{2}{3}$

Step-by-step explanation:

Given

$f \left(x,y \right) = \left{ \begin{array} { l l } { k , } & { 0 \leq x} \leq 2,0 \leq y \leq 1,2 y \leq x } & { \text 0, { elsewhere. } } \end{array} \right.$

Solving (a):

Find k

To solve for k, we use the definition of joint probability function:

$\int\limits^a_b \int\limits^a_b {f(x,y)} \, = 1$

Where

${ 0 \leq x} \leq 2,0 \leq y \leq 1,2 y \leq x }$

Substitute values for the interval of x and y respectively

So, we have:

$\int\limits^2_{0} \int\limits^{x/2}_{0} {k\ dy\ dx} \, = 1$

Isolate k

$k \int\limits^2_{0} \int\limits^{x/2}_{0} {dy\ dx} \, = 1$

Integrate y, leave x:

$k \int\limits^2_{0} y {dx} \, [0,x/2]= 1$

Substitute 0 and x/2 for y

$k \int\limits^2_{0} (x/2 - 0) {dx} \,= 1$

$k \int\limits^2_{0} \frac{x}{2} {dx} \,= 1$

Integrate x

$k * \frac{x^2}{2*2} [0,2]= 1$

$k * \frac{x^2}{4} [0,2]= 1$

Substitute 0 and 2 for x

$k *[ \frac{2^2}{4} - \frac{0^2}{4} ]= 1$

$k *[ \frac{4}{4} - \frac{0}{4} ]= 1$

$k *[ 1-0 ]= 1$

$k *[ 1]= 1$

$k = 1$

Solving (b): $P(x > 3y)$

We have:

$f(x,y) = k$

Where $k = 1$

$f(x,y) = 1$

To find $P(x > 3y)$ , we use:

$\int\limits^a_b \int\limits^a_b {f(x,y)}$

So, we have:

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {f(x,y)} dxdy$

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {1} dxdy$

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 dxdy$

Integrate x leave y

$P(x > 3y) = \int\limits^2_0 x [0,y/3]dy$

Substitute 0 and y/3 for x

$P(x > 3y) = \int\limits^2_0 [y/3 - 0]dy$

$P(x > 3y) = \int\limits^2_0 y/3\ dy$

Integrate

$P(x > 3y) = \frac{y^2}{2*3} [0,2]$

$P(x > 3y) = \frac{y^2}{6} [0,2]\\$

Substitute 0 and 2 for y

$P(x > 3y) = \frac{2^2}{6} -\frac{0^2}{6}$

$P(x > 3y) = \frac{4}{6} -\frac{0}{6}$

$P(x > 3y) = \frac{4}{6}$

$P(x > 3y) = \frac{2}{3}$

8 0

2 years ago

If two triangles are congruent, which of the following statements must be

Burka [1]

Answer:

[A] The corresponding sides of the triangles are congruent.

[B] The corresponding angles of the triangles are congruent.

[C] The triangles have the same size.

[D] The triangles have the same shape.

Step-by-step explanation:

SAS which it is stands for {side, angle, side} and the meaning of SAS is that we have two triangles where we see two sides and the included angle are equal.

In Order for two triangles to be congruent must have the following below:

Two figures are said to be congruent if they have same size and same shape.
If two figure are congruent that means the corresponding sides will also be congruent.
If two figure are congruent that means the the corresponding angles will also be congruent.

Hence, base on the given all the following are correct:

A. The corresponding sides of the triangles are congruent. √

B. The corresponding angles of the triangles are congruent. √

C. The triangles have the same size. √

D. The triangles have the same shape. √

<u><em>Kavinsky</em></u>

7 0

1 year ago

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Question 1

Alexxx [7]

Answer:

Water needed for pool = 486 cubic feet

Plastic liner required for the pool = 298.3 feet

Step-by-step explanation:

Top view of the pool is a composite figure, having one rectangle and a trapezoid.

1). Water needed for the pool = volume of the pool

Volume of the pool = Area of the base × Depth

= (Area of the rectangle + Area of the trapezoid)× depth

Area of the trapezoid = $\frac{1}{2}(b_{1}+b_{2})\times h$

= $\frac{1}{2}(11+9)\times (12-1.5)$

= 105 ft²

Area of the rectangle = Length × width

= 11 × 1.5

= 16.5 ft²

Now, volume of the pool = (105 + 16.5) × 4

= 121.5 × 4

= 486 cubic feet

b). Liner required = surface area of the pool excluding top

= Surface area of the walls + Area of the pool base

= (Perimeter of the pool) × depth + area of the base

= (12 + 11 + 1.5 + 10.7 + 9)×4 + 121.5

= 176.8 + 121.5

= 298.3 square feet

Therefore, amount of water required = 486 cubic feet

liner needed = 298.3 square feet

8 0

2 years ago