Answer:
The equation for difference in altitude of the two helicopters is A = 650 - 100t
Step-by-step explanation:
Given;
The altitude of one helicopter is, A1 = 600 + 150t
The altitude of a second helicopter is, A2 = 1250 + 50t
Their difference in altitude, A at time t, is calculated as
A₂ - A₁ = A = (1250 + 50t) - (600 + 150t)
A₂ - A₁ = A = 1250 + 50t - 600 -150t
A₂ - A₁ = A = 1250 - 600 + 50t - 150t
A₂ - A₁ = A = 650 - 100t
Therefore, the equation for difference in altitude of the two helicopters is A = 650 - 100t
Answer:
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Step-by-step explanation:
bwjsfehoal topu
Here we use altitude rule which states that
Ratio of part of hypotenuse and height= ratio of height and remaining part of hypotenuse .
So here parts of hypotenuses are r and s and h is the hypotenuse. SO we will get
Correct option is s.
Multiply all terms by x and cancel:<span><span>6+<span>2x</span></span>=<span><span>3x</span>4</span></span><span><span><span>2x</span>+6</span>=<span><span>34</span>x</span></span>(Simplify both sides of the equation)<span><span><span><span>2x</span>+6</span>−<span><span>34</span>x</span></span>=<span><span><span>34</span>x</span>−<span><span>34</span>x</span></span></span>(Subtract 3/4x from both sides)<span><span><span><span>54</span>x</span>+6</span>=0</span><span><span><span><span><span>54</span>x</span>+6</span>−6</span>=<span>0−6</span></span>(Subtract 6 from both sides)<span><span><span>54</span>x</span>=<span>−6</span></span><span><span><span>(<span>45</span>)</span>*<span>(<span><span>54</span>x</span>)</span></span>=<span><span>(<span>45</span>)</span>*<span>(<span>−6</span>)</span></span></span>(Multiply both sides by 4/5)<span>x=<span><span>−24</span>5</span></span>Check answers. (Plug them in to make sure they work.)<span>x=<span><span><span>−24</span>5</span></span></span>
