Answer: -9.8
Step-by-step explanation:
Your answer is going to be -20.
Answer:
Yay so cool!!
Step-by-step explanation:
i just wanted free points haha
Answer:
the probability that 0≤x≤1/2 and 1/4≤y≤1/2 is 3/64 (4.68%)
Step-by-step explanation:
assuming that X and Y are independent variables for the probability density function f(x,y) :
f(x,y) = 4*x*y for 0≤x≤1 and 0≤y≤0
f(x,y) = 0 elsewhere
then the probability is calculated through:
P(x,y)= ∫f(x,y) dx dy = ∫4xy dx dy
for 0≤x≤1/2 and 1/4≤y≤1/2 we have
P(0≤x≤1/2,1/4≤y≤1/2 ) = ∫4xy dx dy = ∫4xy dx dy = 4*∫x dx ∫y dx = 4*[((1/2)²/2-0²/2)] *[(1/2)²/2-(1/4)²/2)] = 1 * 1/4 * (1/4-1/16) = 1 * 1/4 * 3/16 = 3/64
then the probability that 0≤x≤1/2 and 1/4≤y≤1/2 is 3/64 (4.68%)