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3 years ago

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Mathematics

1 answer:

Eva8 [605]3 years ago

5 0

The answer is negative twenty five. By the way, if that is you in the picture, you are beautiful.

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Homeroom 101 and homeroom 102 share a hallway bulletin board. if home room 101 uses 3/5 of their half of display artwork what fr

STatiana [176]

To solve this problem you must keep on mind the following information:

The problem says that Homeroom 101 can use a half of display artwork (which is $\frac{1}{2}$ ) and they use $\frac{3}{5}$ . Therefore, you only need to multiply both fractions, as following:

$(\frac{1}{2} )(\frac{3}{5} )=\frac{3}{10}$

Therefore, as you can see, the answer is: $\frac{3}{10}$ of the bulletin board is used to display Homeroom 101’s artwork.

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3 years ago

A population of 800 spiders is decreasing at a rate of 14% each week. How many weeks will it take for the population to be half

Marrrta [24]

Answer:

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3 years ago

What is the answer if you expand -7(k - 3)

Katyanochek1 [597]

The answer is -7k + 21

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3 years ago

On Tuesday, a local retail store is offered an additional 20% off all school supplies. Before you handed cashier the 20% off cou

inysia [295]

I think it would be $8.64

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4 years ago

Explain how to find each root, with its multiplicity, for the polynomial y=x^5-27x^2.

Nuetrik [128]

The roots of $y = x^{5}-27\cdot x^{2}$ are 0 (multiplicity 2), -3 (multiplicity 1), $-\frac{3}{2}+i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1) and $-\frac{3}{2}-i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1).

The characteristics of the polynomial can be derived from algebraic techniques. Roots and multiplicity can be found by <em>factoring</em> the polynomial. The multiplicity is represented by a power binomial of the form:

$(x-r_{i})^{m},\,m \le n$ (1)

Where $n$ is the grade of the polynomial.

Now we proceed to factor the formula:

$y = x^{5}-27\cdot x^{2}$

$y = x^{2}\cdot (x^{3}-27)$

$y = x^{2}\cdot (x^{2}+3\cdot x +9)\cdot (x-3)$

Please notice that $x^{2}+3\cdot x + 9$ have two complex roots.

$y = x^{2}\cdot \left(x+\frac{3}{2}-i\,\frac{3\sqrt{3}}{2} \right)\cdot \left(x+\frac{3}{2}+i\,\frac{3\sqrt{3}}{3} \right)\cdot (x-3)$

The roots of $y = x^{5}-27\cdot x^{2}$ are 0 (multiplicity 2), -3 (multiplicity 1), $-\frac{3}{2}+i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1) and $-\frac{3}{2}-i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1).

We kindly invite to see this question on polynomials: brainly.com/question/1218505

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3 years ago