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Tanya [424]
3 years ago
8

....................................................................

Mathematics
1 answer:
Eva8 [605]3 years ago
5 0
The answer is negative twenty five. By the way, if that is you in the picture, you are beautiful.
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Homeroom 101 and homeroom 102 share a hallway bulletin board. if home room 101 uses 3/5 of their half of display artwork what fr
STatiana [176]

To solve this problem you must keep on mind the following information:

The problem says that Homeroom 101 can use a half of display artwork (which is \frac{1}{2}) and they use \frac{3}{5}. Therefore, you only need to multiply both fractions, as following:

(\frac{1}{2} )(\frac{3}{5} )=\frac{3}{10}

Therefore, as you can see, the answer is: \frac{3}{10} of the bulletin board is used to display Homeroom 101’s artwork.

4 0
3 years ago
A population of 800 spiders is decreasing at a rate of 14% each week. How many weeks will it take for the population to be half
Marrrta [24]

Answer:

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5 0
3 years ago
What is the answer if you expand -7(k - 3)
Katyanochek1 [597]
The answer is -7k + 21
7 0
3 years ago
On Tuesday, a local retail store is offered an additional 20% off all school supplies. Before you handed cashier the 20% off cou
inysia [295]
I think it would be $8.64
6 0
4 years ago
Explain how to find each root, with its multiplicity, for the polynomial y=x^5-27x^2.
Nuetrik [128]

The roots of y = x^{5}-27\cdot x^{2} are 0 (multiplicity 2), -3 (multiplicity 1), -\frac{3}{2}+i\,\frac{3\sqrt{3}}{2} (multiplicity 1) and -\frac{3}{2}-i\,\frac{3\sqrt{3}}{2} (multiplicity 1).

The characteristics of the polynomial can be derived from algebraic techniques. Roots and multiplicity can be found by <em>factoring</em> the polynomial. The multiplicity is represented by a power binomial of the form:

(x-r_{i})^{m},\,m \le n (1)

Where n is the grade of the polynomial.

Now we proceed to factor the formula:

y = x^{5}-27\cdot x^{2}

y = x^{2}\cdot (x^{3}-27)

y = x^{2}\cdot (x^{2}+3\cdot x +9)\cdot (x-3)

Please notice that x^{2}+3\cdot x + 9 have two complex roots.

y = x^{2}\cdot \left(x+\frac{3}{2}-i\,\frac{3\sqrt{3}}{2}  \right)\cdot \left(x+\frac{3}{2}+i\,\frac{3\sqrt{3}}{3}  \right)\cdot (x-3)

The roots of y = x^{5}-27\cdot x^{2} are 0 (multiplicity 2), -3 (multiplicity 1), -\frac{3}{2}+i\,\frac{3\sqrt{3}}{2} (multiplicity 1) and -\frac{3}{2}-i\,\frac{3\sqrt{3}}{2} (multiplicity 1).

We kindly invite to see this question on polynomials: brainly.com/question/1218505

7 0
3 years ago
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