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puteri [66]
2 years ago
5

Solve the two-step equation. -9x 0. 4 = 4 Which operation must be performed to move all the constants to the right side of the e

quation? Then, which operation must be performed to isolate the variable? The solution to the equation is x =.
Mathematics
1 answer:
AlekseyPX2 years ago
3 0

The steps needed to solve the given equation is required.

Adding the opposite value of the constant to both sides.

Divide both sides by the coefficient of the variable.

The solution to the equation is  

The given equation is

In order to solve this we first move constants to the side opposite of the variable.

This is done by adding the opposite value of the constant to both sides.

Here  is the constant so we add  to both sides.

Now, we divide both sides by the coefficient of the variable.

The solution to the equation is

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0.81 (rounded to the nearest hundredth) & 81%

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0.81 is 81%

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Suppose we roll a fair six-sided die 20 times and draw ten cards from a standard 52-card deck. Let X be the number of "6"s rolle
Lera25 [3.4K]

Answer:

a) Expected value = 6.406

Variance = 4.905

Standard deviation = 2.45

b) The probability is 0.08547

Step-by-step explanation:

a) Let's suppose that:

X₁ = number of 6´s

X₂ = number of Jack, Queen, King or Aces

The mean of X₁ is:

MeanX₁ = n * p = 20 * (1/6) = 3.33

The variance of X₁ is:

Var-X_{1} =np(1-p)=3.33(1-(1/6))=2.775

The mean of X₂ is:

MeanX₂ = 10 * (16/52) = 3.076

The variance of X₂ is:

Var-X_{2} =3.076(1-(16/52))=2.13

The expect value of X is:

Xexp = MeanX₁ + MeanX₂ = 3.33 + 3.076 = 6.406

The variance of X is:

VarX = VarX₁ + VarX₂ = 2.775 + 2.13 = 4.905

The standard deviation is:

Xdevi = 4.905/2 = 2.45

b) The probability of drawing at least five six out of 20 rolls is equal to:

∑(1/6)ˣ(5/6)²⁰⁻ˣ = 0.231 with x = 5

The probability of at least 4 Jack, Queen, Kings or Aces is:

∑(16/52)ˣ(1-(16/52))¹⁰⁻ˣ = 0.37 with x = 4

The probability of given event is equal to:

P = 0.231 * 0.37 = 0.08547

5 0
3 years ago
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