The object should be placed 20/cm from the lens so as to form its real image on the screen
<h3>Mirror equation</h3>
The mirror equation is given according to the expression below;
1/f = 1/u + 1/v
where
f is the focal length
u is the object distance
v is the image distance
Given the following parameters
f = 5cm
v = 20cm
Required
object distance u
Substitute
1/5 = 1/u +1/20
1/u = 1/5-1/20
1/u = 3/20
u = 20/3 cm
Hence the object should be placed 20/cm from the lens so as to form its real image on the screen
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Answer:
A
Step-by-step explanation:
I think it's A because it mostly multiplies then adds and subtracts so you get your answer doing this
Answer:
<h2>
10. C. (2, -1)</h2><h2>
11. B. (-2, -4)</h2>
Step-by-step explanation:
10.

The y values cancel out if you add the equations
5x = 10
x = 2
plug in x
2 - 2y = 4
-2y = 2
y=-1
Answer: C. (2, -1)
11.

In order to get terms to cancel out, multiply the top by 3 and bottom by 2

The y values cancel out if you add the equations
10x = -20
x = -2
plug in x
6(-2) - 2y = -4
-12 - 2y = -4
-2y = 8
y = -4
Answer: B. (-2, -4)
Answer:
80 points
Step-by-step explanation:
400 x 0.20% = 80
Answer:
-8
Step-by-step explanation:
(-2)(-2)(-2)
4(-2)
-8