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Serga [27]
3 years ago
11

Find the sum or difference 1/2 - 1/14 A.3/7 B.2/7 C.4/7

Mathematics
1 answer:
pogonyaev3 years ago
7 0

Answer:

A.3/7

Step-by-step explanation:

1/2 - 1/14

We need to get a common denominator of 14

1/2 * 7/7 = 7/14

7/14 - 1/14 = 6/14

We can simplify by dividing the top and bottom by 2

3/7

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A 6 ounce hamburger contains 0.75 ounces of fat
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1. The height of a missile t seconds after it has been fired is given by h=4.9t^2+44.1t. How many seconds will it take for the r
asambeis [7]

Answer:

The rocket will take 4.5 seconds to reach its maximum height.

Step-by-step explanation:

The height of a missile t seconds after it has been fired is given by h=-4.9*t²+44.1*t

This function is a quadratic function of the form f (x) = a*x² + b*x + c. In this case a=-4.9, b=44.1 and c=0

To calculate how many seconds it will take for the rocket to reach its maximum height, I must calculate the maximum of the function. The maximum of a quadratic function is the vertex of the parabola. The x coordinate of the vertex will be simply: x=\frac{-b}{2*a}. The y coordinate of the vertex corresponds to the function evaluated at that point.

In this case the x coordinate of the vertex corresponds to the t coordinate. In other words, by calculating the x coordinate of the vertex, you are calculating the maximum time t it will take for the rocket to reach its maximum height. So:

t=\frac{44.1}{2*(-4.9)}

t=4.5

<u><em>The rocket will take 4.5 seconds to reach its maximum height.</em></u>

7 0
2 years ago
Consider the function V=g(x), where g(x) =x(6-2x)(8-2x), with x being the length of a cutout in cm and V being the volume of an
Andrej [43]

Answer:

The maximum volume of the open box is 24.26 cm³

Step-by-step explanation:

The volume of the box is given as V=g(x), where g(x)=x(6-2x)(8-2x) and 0\le x\le3.

Expand the function to obtain:

g(x)=4x^3-28x^2+48x

Differentiate  wrt  x to obtain:

g'(x)=12x^2-56x+48

To find the point where the maximum value occurs, we solve

g'(x)=0

\implies 12x^2-56x+48=0

\implies x=1.13,x=3.54

Discard x=3.54 because it is not within the given domain.

Apply the second derivative test to confirm the maximum critical point.

g''(x)=24x-56, g''(1.13)=24(1.13)-56=-28.88\:

This means the maximum volume occurs at x=1.13.

Substitute x=1.13 into g(x)=x(6-2x)(8-2x) to get the maximum volume.

g(1.13)=1.13(6-2\times1.13)(8-2\times1.13)=24.26

The maximum volume of the open box is 24.26 cm³

See attachment for graph.

6 0
4 years ago
Please help, I'll mark brainliest.
GREYUIT [131]
I'm almost certain it's C :)
8 0
3 years ago
Yesterday morning, the temperature was -11. The temperature increased 7 by noon and then decreased 4 by nightfall. What was the
tamaranim1 [39]

Answer:

-8 is the answer

Step-by-step explanation:

6 0
3 years ago
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