Answer:
Flow charts help programmers develop the most efficient coding because they can clearly see where the data is going to end up. Flow charts help programmers figure out where a potential problem area is and helps them with debugging or cleaning up code that is not working.
creds to study.com (please don't copy it work by word, make sure to paraphrase it. otherwise plagiarism is in the game.)
Explanation:
Here is the answer: <span>Tunneling</span>
<h2>
Answer:</h2>
F = 13
<h2>
Explanation:</h2>
Given:
x = false
y = 5
z = 1
F = (4%2)+2*Y +6/2 +(z&&x)
We solve this arithmetic using the order of precedence:
<em>i. Solve the brackets first</em>
=> (4 % 2)
This means 4 modulus 2. This is the result of the remainder when 4 is divided by 2. Since there is no remainder when 4 is divided by 2, then
4 % 2 = 0
=> (z && x)
This means (1 && false). This is the result of using the AND operator. Remember that && means AND operator. This will return false (or 0) if one or both operands are false. It will return true (or 1) if both operands are true.
In this case since the right operand is a false, the result will be 0. i.e
(z && x) = (1 && false) = 0
<em>ii. Solve either the multiplication or division next whichever one comes first.</em>
=> 2 * y
This means the product of 2 and y ( = 5). This will give;
2 * y = 2 * 5 = 10
=> 6 / 2
This means the quotient of 6 and 2. This will give;
6 / 2 = 3
<em>iii. Now solve the addition by first substituting the values calculated earlier back into F.</em>
F = (4%2)+2*Y +6/2 +(z&&x)
F = 0 + 10 + 3 + 0
F = 13
Therefore, the value of F is 13
Answer:
public static void PrintShampooInstructions(int numberOfCycles){
if (numberOfCycles<1){
System.out.println("Too Few");
}
else if(numberOfCycles>4){
System.out.println("Too many");
}
else
for(int i = 1; i<=numberOfCycles; i++){
System.out.println(i +": Lather and rinse");
}
System.out.println("Done");
}
Explanation:
I have used Java Programming language to solve this
Use if...elseif and else statement to determine and print "Too Few" or "Too Many".
If within range use a for loop to print the number of times
