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Fed [463]
2 years ago
6

Mia's work to find the slope of a trend line through the points (3, 10) and (35, 91) is shown below. Mia's Work Step 1 StartFrac

tion 3 minus 35 Over 10 minus 91 EndFraction Step 2 StartFraction negative 32 Over negative 81 EndFraction Step 3 StartFraction 32 Over 81 EndFraction What was the first error that Mia made?
Mathematics
1 answer:
gogolik [260]2 years ago
7 0

Answer:

Mia switched the numerator and the denominator.

Step-by-step explanation:

i got it right on edge 2020

and uh also because its y2 - y1 over x2 - x1, not x2 - x1 over y2-y1.

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Please help !! I’m really stressed and soo confused
UkoKoshka [18]

36. NOTA

37. 456 mm

38. 510 oz

7 0
3 years ago
I NEED IMMEDIATE HELP!!!!
DerKrebs [107]
<h2>Hello!</h2>

The answers are:

C) (3+xz)(-3+xz)

D) (y^2-xy)(y^2+xy)

F) (64y^2+x^2)(-x^2+64y^2)

<h2>Why?</h2>

To know which of the products results in a difference of square, we need to remember the difference of squares from:

The difference of squares form is:

(a+b)(a-b)=a^{2}-b^{2}

So, discarding each of the given options in order to find which products result in a difference of squares, we have:

<h2>A)</h2>

(x-y)(y-x)=xy-x^{2}-y^{2} +yx=-x^{2} -y^{2}

So, the obtained expression is not a difference of squares.

<h2>B)</h2>

(6-y)(6-y)=36-6y-6y+y^{2}=y^{2}-12y+36

So, the obtained expression is not a difference of squares.

<h2>C)</h2>

(3+xz)(-3+xz) =(xz+3)(xz-3)=(xz)^{2}-3xz+3xz-(3)^{2}\\\\(xz)^{2}-3xz+3xz-(3)^{2}=(xz)^{2}-(3)^{2}

So, the obtained expression is a difference of squares since it matches with the form of the difference of squares.

<h2>D)</h2>

(y^2-xy)(y^2+xy)=(y^{2})^{2}+y^{2}*xy-y^{2}*xy-(xy)^{2} \\\\(y^{2})^{2}+y^{2}*xy-y^{2}*xy-(xy)^{2}=(y^{2})^{2}-(xy)^{2}

So, the obtained expression is a difference of squares since it matches with the form of the difference of squares.

<h2>E)</h2>

(25x-7y)(-7y+25x)=-175xy+(25x)^{2}+49y^{2}-175xy\\\\-175xy+(25x)^{2}+49y^{2}-175xy=(25x)^{2}+49y^{2}-350xy

So, the obtained expression is not a difference of squares

<h2>F)</h2>

(64y^2+x^2)(-x^2+64y^2)=(64y^2+x^2)(64y^2-x^2)\\\\(64y^2+x^2)(64y^2-x^2)=(64y^{2})^{2} -(x^{2}*64y^{2})+(x^{2}*64y^{2})-(x^{2})^{2}\\ \\(64y^{2})^{2} -(x^{2}*64y^{2})+(x^{2}*64y^{2})-(x^{2})^{2}=(64y^{2})^{2}-(x^{2})^{2}

So, the obtained expression is a difference of squares since it matches with the form of the difference of squares.

Hence, the products that result in a difference of squares are:

C) (3+xz)(-3+xz)

D) (y^2-xy)(y^2+xy)

F) (64y^2+x^2)(-x^2+64y^2)

Have a nice day!

5 0
3 years ago
There are 3,141 students at a concert. If there are 9 seats in each row, how many rows will the students need?
professor190 [17]

Answer:

349

Step-by-step explanation:

3141 divided by 9=349

4 0
3 years ago
If 5 volunteers can wash 100 cars in 5 hours, find<br> the constant of variation.
valina [46]

Answer:

20

Step-by-step explanation:

if you want to vary how many one can do in 5 hours you just have to subtract 5 from 100. need help just come to me

4 0
2 years ago
Identify each expression and value that represents the area under the curve y=x^2+4 on the interval [-3,2]
Alina [70]

The area under a graph is given by the integral of that function, evaluated in the interval of interest:

\displaystyle \int_{-3}^2 x^2+4\;dx = \left[\dfrac{x^3}{3}+4x\right]_{-3}^2 = \left[\dfrac{2^3}{3}+4\cdot 2\right]-\left[\dfrac{(-3)^3}{3}+4\cdot(-3)\right] = \left[\dfrac{8}{3}+8\right]-\left[-9-12\right] = \dfrac{32}{3}+21 = \dfrac{95}{3}

8 0
2 years ago
Read 2 more answers
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