Here is your equation:
![12x-5=127](https://tex.z-dn.net/?f=12x-5%3D127)
You're trying to find x, and to do that, the variable must be alone. That means you need to cancel out everything with it. The only thing with the variable 12x is -5. To cancel that out, you have to do the opposite of it, which is +5. Add 5 to both sides.
![12x-5+5=127+5 \\12x=132](https://tex.z-dn.net/?f=12x-5%2B5%3D127%2B5%20%5C%5C12x%3D132)
12x(12 times x) is equal to 132. You need to find x. You have to do the opposite of times 12, which is divide by 12. Divide both sides by 12.
![\frac{12x}{12} = \frac{132}{12} \\ \\x=11](https://tex.z-dn.net/?f=%5Cfrac%7B12x%7D%7B12%7D%20%3D%20%5Cfrac%7B132%7D%7B12%7D%20%5C%5C%20%5C%5Cx%3D11)
Your answer is x is equal to 11 ; x = 11
<em>If you have any questions, feel free to ask in the comments! :)</em>