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Lilit [14]
3 years ago
13

What is 12x - 5 = 127

Mathematics
1 answer:
Elina [12.6K]3 years ago
3 0

Here is your equation:

12x-5=127

You're trying to find x, and to do that, the variable must be alone. That means you need to cancel out everything with it. The only thing with the variable 12x is -5. To cancel that out, you have to do the opposite of it, which is +5. Add 5 to both sides.

12x-5+5=127+5 \\12x=132

12x(12 times x) is equal to 132. You need to find x. You have to do the opposite of times 12, which is divide by 12. Divide both sides by 12.

\frac{12x}{12} = \frac{132}{12} \\ \\x=11

Your answer is x is equal to 11 ; x = 11

<em>If you have any questions, feel free to ask in the comments! :)</em>

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The residual value, which is the farthest from the line of best fit for the table which shows points and their residual values, is 0.7.

<h3>What is residual value?</h3>

The residual value is the estimated value which is calculated for the end of the lease terms for a fixed asset.

Points and their residual values are shown in the table. A 3-column table with 5 rows.

  •  x                               1,     2,     3,     4,     5.
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The simple regression line can be represented as,

\hat y=\alpha +\beta X+\hat e

Here α is the constant, β is the slope and <em>e </em>is the residue.

The point which is farthest from the best fit of the line is 3.5. At y=3.5, the value of residue is 0.7.

Thus, the residual value, which is the farthest from the line of best fit for the table which shows points and their residual values, is 0.7.

Learn more about the residual value here;

brainly.com/question/1168961

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The sum of the cost of a veterinarian exam v and a $50 x-ray tip divided equally between 2 people.
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Find the exact value of tan( cos^-1 ( -5/13))
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Answer:

-¹²/₅  

Step-by-step explanation:

Let cos a = -⁵/₁₃

Then tan a = sin a/cos a

= [√(1 - cos²a)]/cos a

= {√[1 - (-⁵/₁₃)²]}/(-⁵/₁₃)

= -[√(1 - ²⁵/₁₆₉)] × ¹³/₅

= -[(√(¹⁴⁴/₁₆₉ )] × ¹³/₅

= -¹²/₁₃ × ¹³/₅

= -¹²/₅

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Answer:

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where \mu is the mean amount of CO_2 emitted by burning one gallon of this new gasoline.

If the null hypothesis is false, then:

H_a: \mu < 8.9 kg

A rejection of the alternate hypothesis above will be a Type II error.

Therefore:

The Type II error is: (B) The mean amount of CO_2  emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg.

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