Answer:
The angle formed between CF and the plane ABCD is approximately 47.14°
Step-by-step explanation:
The given parameters are;
BC = 6.8
DE = 9.3
∠BAC = 52°
We note that the angles formed by the vertex of a cuboid are right triangles, therefore, by trigonometric ratios, we get;
sin∠BAC = BC/(The length of a line drawn from A to C)
∴ The length of the line drawn from A to C = BC/sin∠BAC
The length of the line drawn from A to C = 6.8/sin(52°) ≈ 8.63
∴ AC = 8.63
By trigonometry, we have;
The angle formed between CF and the plane ABCD = Angle ∠ACF


In a cuboid, FA = BG = CH = DE = 9.3


The angle formed between CF and the plane ABCD = Angle ∠ACF ≈ 47.14°
Ummm We can’t solve it without the pictures
Answer:
(0,-1), y, 3, 3 up, 1 right
(0,1), y, 1 up, 1 right
Step-by-step explanation:
just fill in the blanks in the order of these answers
Answer:
50.41 minus 1.71 is 48.70 divided by 5 is 9.74