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Ivan
3 years ago
12

Find the difference of the following sequence: -7, -9, -11... Difference: ___

Mathematics
2 answers:
Anna007 [38]3 years ago
3 0
Hmmmmmm I think I know the answer to this
Alecsey [184]3 years ago
3 0
-2 during every term
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Which of the following formulas would find the lateral
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3 years ago
Need answers for 70-75
adoni [48]

Answer:

70. 0

71. -54

72. 12

73. 86

74. 59

Step-by-step explanation:

To evaluate an expression, substitute specific values for the variables and simplify using Order of Operations.

70. c-3d becomes

(1)-3(\frac{1}{3}) = 1-(\frac{3}{3}) = 1-1 = 0

71. x+x^3-4x^4 becomes

2+2^3-4(2)^4 = 2+8-4(16) = 2+8-64=10-64=-54

72. 5a+3a^2 becomes

5(-3)+3(-3)^2 = -15 +3(9) = -15 + 27 = 12

73. F=\frac{9}{5}C+32 becomes

F=\frac{9}{5}(30)+32=\frac{270}{5}+32 = 54+32 = 86

74.  F=\frac{9}{5}C+32 becomes

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8 0
3 years ago
Trevon’s school is selling tickets to a fall musical. On the first day of ticket sales the school sold 13 adult tickets and 12 s
julsineya [31]

9514 1404 393

Answer:

  • adult: $7
  • student: $10

Step-by-step explanation:

Let a and s represent the prices of adult and student tickets, respectively.

  13a +12s = 211 . . . . . . ticket sales the first day

  5a +3s = 65 . . . . . . . ticket sales the second day

Subtracting the first equation from 4 times the second gives ...

  4(5a +3s) -(13a +12s) = 4(65) -(211)

  7a = 49 . . . . . . . simplify

  a = 7 . . . . . . . divide by 7

  5(7) +3s = 65 . . . . substitute into the second equation

  3s = 30 . . . . . . . subtract 35

  s = 10 . . . . . . . divide by 3

The price of one adult ticket is $7; the price of one student ticket is $10.

7 0
3 years ago
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