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Romashka-Z-Leto [24]
4 years ago
14

HELP PLEASE WILL GIVE ALOT OF POINTS

Mathematics
2 answers:
White raven [17]4 years ago
8 0

Angle O is correspondent with the position of angle D.

alexgriva [62]4 years ago
8 0

Which angle in the pre-image corresponds to D in the image?

The angle that corresponds is Angle O!

You might be interested in
Please solve needed as soon as possible thank you I really appreciate it
e-lub [12.9K]

Answer:

143

Step-by-step explanation:

Substitute n=3 into the problem

6(3^{3})-2(3^{2}) +3-4

Then figure out squared and power by 3

6(27)-2(9)+3-4

Next multiply

162-18+3-4

Finally, add and subtract

144+3=147

147-4=143

8 0
3 years ago
What is 7(n+4)=21 ?
navik [9.2K]

Answer:

n=-1

Step-by-step explanation:

7n + 28 = 21

subtract 28 on both sides

7n= -7

divide by seven on both sides

n= -1

8 0
3 years ago
Read 2 more answers
dos aviones parten de una ciudad con direcciones S32°E y E57°N¿ cuál es el angulo que forma sus direcciones?​
Elan Coil [88]

Answer:

El ángulo formado entre las dos direcciones es aproximadamente 115º.

Step-by-step explanation:

Las direcciones dadas en el enunciado significan lo siguiente:

S32ºE - <em>32º al este del sur.</em>

E57ºN - <em>57º al norte del este.</em>

Vectorialmente hablando, cada dirección es la siguiente:

S32ºE

A(x,y) = (\sin 32^{\circ}, -\cos 32^{\circ})

A(x,y) = (0.530, -0.848)

E57ºN

B(x,y) = (\cos 57^{\circ},\sin 57^{\circ})

B(x,y) = (0.545, 0.839)

El ángulo formado entre los dos vectores unitarios (\theta), medido en grado sexagesimales, puede determinarse mediante la siguiente ecuación vectorial:

\theta = \cos^{-1} \frac{A\,\bullet \,B}{\|A\|\cdot \|B\|}

Donde:

\|A\| - Norma de A(x,y).

\|B\| - Norma de B(x,y).

Si sabemos que A(x,y) = (0.530, -0.848), B(x,y) = (0.545, 0.839), \|A\| = 1 y \|B\| = 1, entonces el ángulo formado entre los dos vectores es:

\theta = \cos^{-1} \frac{(0.530)\cdot (0.545)+(-0.848)\cdot (0.839)}{(1)\cdot (1)}

\theta \approx 115^{\circ}

El ángulo formado entre las dos direcciones es aproximadamente 115º.

4 0
3 years ago
A medicine is decaying at a rate of 5% per hour. If there were initially 1000mg of the medicine, how much is left after 4 hours?
Stolb23 [73]

Answer:

  814.5 mg remain after 4 hours

Step-by-step explanation:

The multiplier of the original quantity is 1 -5% = 0.95 for each passing hour. The amount remaining after x hours is ...

  y = 1000·0.95^x

For x=4, the amount remaining is ...

  y = 1000·0.95^4 = 1000·0.81450625

  y ≈ 814.5 . . . mg remain after 4 hours

8 0
3 years ago
What line passes into the points of -2,1 and 3- -1?
nikdorinn [45]

The line that passes through points (-2,1) and (3,-1) is a negative slope

4 0
3 years ago
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