Answer:
(7, 24, 26)
Step-by-step explanation:
A Pythagorean triple must have an odd number of even numbers. The triple (7, 24, 26) is not a Pythagorean triple.
_____
<em>Additional comment</em>
For an odd integer n, a triple can be formed as ...
(n, (n²-1)/2, (n²+1)/2)
That is, the following will be Pythagorean triples.
- (3, 4, 5)
- (5, 12, 13)
- (7, 24, 25)
- (9, 40, 41)
- (11, 60, 61)
Another series involves even numbers and numbers separated by 2:
(2n, n²-1, n²+1)
- (8, 15, 17)
- (12, 35, 37)
- (16, 63, 65)
In this list, if n is not a multiple of 2, the triple will be a multiple of one from the odd-number series.
It is a good idea to remember a few of these, as they tend to show up in Algebra, Geometry, and Trigonometry problems.
2+2=2x+2
-2 to both sides
2=2x
Divide 2
X=1
Answer:
Step-by-step explanation:
![\sf 2x + 4(7-x) \\\\Resolving \ Parenthesis\\\\2x + 28-4x \\\\Combining\ like\ terms\\\\2x-4x +28\\\\-2x + 28\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%202x%20%2B%204%287-x%29%20%20%5C%5C%5C%5CResolving%20%5C%20Parenthesis%5C%5C%5C%5C2x%20%2B%2028-4x%20%5C%5C%5C%5CCombining%5C%20like%5C%20terms%5C%5C%5C%5C2x-4x%20%2B28%5C%5C%5C%5C-2x%20%2B%2028%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
![\sf \\12x-(4+2x)\\\\12x-4-2x\\\\Combining \ like \ terms\\\\12x-2x - 4\\\\10x-4 \\\\\rule[22]{225}{2} \\2(10-x)+3(12-x) \\\\Resolving \ Parenthesis\\\\20-2x + 36 -3x\\\\Combining \ like \ terms\\\\20+36 -2x-3x\\\\56 - 5x \\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20%5C%5C12x-%284%2B2x%29%5C%5C%5C%5C12x-4-2x%5C%5C%5C%5CCombining%20%5C%20like%20%5C%20terms%5C%5C%5C%5C12x-2x%20-%204%5C%5C%5C%5C10x-4%20%5C%5C%5C%5C%5Crule%5B22%5D%7B225%7D%7B2%7D%20%5C%5C2%2810-x%29%2B3%2812-x%29%20%5C%5C%5C%5CResolving%20%5C%20Parenthesis%5C%5C%5C%5C20-2x%20%2B%2036%20-3x%5C%5C%5C%5CCombining%20%5C%20like%20%5C%20terms%5C%5C%5C%5C20%2B36%20-2x-3x%5C%5C%5C%5C56%20-%205x%20%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
![\sf 7(x-1)-6(x+1)\\\\Resolving \ Parethesis\\\\7x-7-6x-6\\\\Combining \ like \ terms\\\\7x-6x-7-6\\\\x - 13\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%207%28x-1%29-6%28x%2B1%29%5C%5C%5C%5CResolving%20%5C%20Parethesis%5C%5C%5C%5C7x-7-6x-6%5C%5C%5C%5CCombining%20%5C%20like%20%5C%20terms%5C%5C%5C%5C7x-6x-7-6%5C%5C%5C%5Cx%20-%2013%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
~AnonymousHelper1807
Answer:
35 mi²
Step-by-step explanation:
Let's subdivide the figure, as shown.
The lower part is a rectangle whose area is (5 mi)(18 mi) = 90 mi².
The upper part is a trapezoid whose area is found by averaging the length and multiplying the result by the width (8 mi - 5 mi), or 3 mi.
Area of trapezoid:
12 mi + 18 mi
------------------------ = 15 mi Width of trapezoid = 3 mi
2
Thus, the area of the trapezoid is (3 mi)(15 mi) = 45 mi²
and the total area of the entire figure is
45 mi² + 90 mi² = 135 mi²
I’m not that sure but
B is (-2,2)
A is (-4,-2)
C is (2,2)
Hope it helps!!
