3.4, 3 + 0.4, three point four
5.8, 5 + 0.8, five point eight
6.2, 6 + 0.2, six point two
The required distance would be 17.88 units coordinates A(-4,5) and B(12,13) and the horizontal distance is 16 units and the vertical distance is 8 units from A to B which are determined by the graphing method.
<h3>What is the distance between two points?</h3>
The distance between two points is defined as the length of the line segment between two places representing their distance.
Given AB with coordinates A(-4,5) and B(12,13).
The formula of the distance between two points is A(x₁, y₁) and B(x₂, y₂) is given by: d (A, B) = √ (x₂ – x₁)² + (y₂ – y₁) ².
x₁ = -4, y₁ = 5
x₂ = 12, y₂ = 13
distance = √ (12 – (-4))² + (13 – 5)²
distance = √ (12 + 4)² + (8)²
distance = √ (16)² + (8)²
distance = √ (256 + 64)
distance = √320
distance = 17.88 units
The horizontal distance is 16 units and the vertical distance is 8 units from A to B which are determined by the graphing method.
Learn more about the distance between two points here:
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Answer:
AQ = 20 units
Step-by-step explanation:
Comparing triangle AQR to ABC,
= 
= 
cross multiply and make p the subject of formula, we have:
8p (2p+3) = 4p(6p-4)
16
+ 24p = 24
- 16p
24p + 16p = 24
- 16
40p = 8
divide through by 8p,
p = 5
Therefore, AQ = 4p
= 4 × 5
= 20
AQ = 20 units
Answer is A, y us smaller/equal to 2 and y is smaller/equal to X
X=-1
-1x2 + 5x-1 +7 = 0
-7+7 =0
0=0