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3 years ago

Distribute and simplify: 7 (2x - 4) + 2 (3x + 1)

Mathematics

1 answer:

Alenkinab [10]3 years ago

3 0

$7(2x-4)+2(3x+1)\\\\[(7*2x)+(7*-4)]+[(2*3x)+(2*1)]\\\\(14x-28)+(6x+2)\\\\14x+6x-28+2\\\\\\20x-25$

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Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane

liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

Answer:

$Rate = 0.935042^\circ /cm$

Step-by-step explanation:

Given

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$T(x,y) =x\sin2y$

$r = 1m$

$v = 2m/s$

Express the given point P as a unit tangent vector:

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$u = \frac{\sqrt 3}{2}i - \frac{1}{2}j$

Next, find the gradient of P and T using: $\triangle T = \nabla T * u$

Where

$\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j$

So: the gradient becomes:

$\triangle T = \nabla T * u$

$\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]$

By vector multiplication, we have:

$\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}$

$\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)$

$\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5$

$\triangle T = 0.935042$

Hence, the rate is:

$Rate = \triangle T = 0.935042^\circ /cm$

3 0

2 years ago

ASAP in 4 math question!

Zepler [3.9K]

1. - 4 = $\frac{x}{9}$

=> x = - 36

___________

2. -18 = 6t

=> t = $\frac{-18}{6}$

=> t = -3

___________

3. x - 18 = -72

=> x = - 72 + 18

=> x = - 54

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4. -18 = x - 15

=> x = -18 + 15

=> x - 3

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2 years ago

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romanna [79]

Answer:

$\boxed{\bold{x \ = \ \frac{5z}{12y} }}$

Explanation:

Solve For X: 12yx = 5z

[ Divide Both Sides By 12y ]

12xy / 12y = 5z / 12y

x = 5z / 12y

- PNW

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Which graph represents the solution set for the quadratic inequality x^2+2x+1 0

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The answer is [-2,7] on e2020, good luck fam

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3 years ago

Eighteen inches is what part of a yard

zaharov [31]

Answer:

The eighth of a yard (4.5 inches) was sometimes called a finger, but was more commonly referred to simply as an eighth of a yard, while the half-yard (18 inches) was called "half a yard".

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Unit system: imperial/US units

Unit of: length

Symbol: yd

Step-by-step explanation:

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