The 15th term in the given A.P. sequence is a₁₅ = 33.
According to the statement
we have given that the A.P. Series with the a = 5 and the d is 2.
And we have to find the 15th term of the sequence.
So, for this purpose we know that the
An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.
And the formula is a
an = a + (n-1)d
After substitute the values in it the equation become
an = 5 + (15-1)2
a₁₅ = 5 + 28
Now the 15th term is a₁₅ = 33.
So, The 15th term in the given A.P. sequence is a₁₅ = 33.
Learn more about arithmetic progression here
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Answer:
x = -3/10
Step-by-step explanation:
Solve for x by substituting y = 3x into the other equation:
2x - 4y = 3
2x - 4(3x) = 3
Simplify and solve for x:
2x - 12x = 3
-10x = 3
x = -3/10
So, x = -3/10
With what? Maybe I can help
Answer:
5y345
Step-by-step explanation:
i did it before
