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LenKa [72]
3 years ago
9

I need help please solve, if you can solve you are the best. \-x+sqrt1−x 2 \-=sqrt2(2x 2 −1).

Mathematics
1 answer:
puteri [66]3 years ago
7 0

Answer:

i think it is 1/4

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Find the polynomial of lowest degree with only real coefficients and having the given zeros. -7i and square root of 2
mario62 [17]

Answer:

x³ - (√2)x² + 49x - 49√2

Step-by-step explanation:

If one root is -7i, another root must be 7i.  You can't just have one root with i.  The other roos is √2, so there are 3 roots.  

x = -7i       is one root,

   (x + 7i) = 0    is the factor

x = 7i       is one root

  (x - 7i) = 0     is the factor

x = √2      is one root

    (x - √2) = 0   is the factor

So the factors are...

(x + 7i)(x - 7i)(x - √2) = 0

Multiply these out to find the polynomial...

(x + 7i)(x - 7i) =  x² + 7i - 7i - 49i²

Which simplifies to

  x² - 49i²        since i² = -1 , we have

    x² - 49(-1)  

 

      x² + 49

Now we have...

(x² + 49)(x - √2) = 0

Now foil this out...

 x²(x) - x²(-√2) + 49(x) + 49(-√2) = 0

     x³ + (√2)x² + 49x - 49√2

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3 years ago
Under the translation T(-5, -2) the point (1, 6) will become (-4, -4).<br><br> True<br><br> False
Butoxors [25]

Step-by-step explanation:

<h3>It's False</h3>

Because (-5+ 1, - 2 + 6) = (- 4, 4) which is not equal to (-4, - 4).

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Answer:

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Step-by-step explanation:

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6x12=72 and72+4=76 soo 76 is your awnser

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Paha777 [63]
1/2, 1/3, 1/4, 1/5, 1/6
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