Question

S1053323

Answer 1

Answer:

$\textbf{ x can take two values 1 or -9 .}$

Step-by-step explanation:

$\textup{Given, {(x + 4)}^2 = 25 }\\\textup{If we take square root on both sides, then we would have:}\\ {(x+4)} = \pm \sqrt{25} = \pm 5 \\ \implies x + 4 = 5 \hspace{15mm} or \hspace{15mm} x + 4 = -5 \\ \implies x = 1 \hspace{22mm} or \hspace{15mm} x = -9 \\\textup{Verify your answer by expanding {(x+4)}^2 = 25 }\\\textup{Solving this we get}\\ x^2 + 8x - 9 = 0 \\\textup{which again yields}\\ x = -9, 1$