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dusya [7]
3 years ago
14

S1053323

Mathematics
1 answer:
marin [14]3 years ago
4 0

Answer:

\textbf{$x$ can take two values $1$ or $-9$.}\\

Step-by-step explanation:

\textup{Given, ${(x + 4)}^2 = 25$}\\\textup{If we take square root on both sides, then we would have:}\\$$ {(x+4)} = \pm \sqrt{25} = \pm 5 $$\\$ \implies x + 4 = 5 \hspace{15mm} $ or \hspace{15mm} $ x + 4 = -5 $\\$ \implies x = 1  \hspace{22mm} $  or \hspace{15mm} $x = -9 $ \\\textup{Verify your answer by expanding ${(x+4)}^2 = 25$}\\\textup{Solving this we get}\\$$ x^2 + 8x - 9 = 0 $$\\\textup{which again yields}\\$$ x = -9, 1 $$

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