We'll call the 2 numbers x and y. Starting with the last part of that first sentence "one number is 10 times the other number" can be written, in algebraic form:

y = 10x

Now on to the first statement about the numbers: "twice their sum" is 2(x + y) and "equals their product" is = xy. Putting that all together:

2(x + y) = xy and we know that y = 10x so

2(x + 10x) = x(10x) and

$2(11x)=10x^2$ and

$10x^2-22x=0$ and

x(10x - 22) = 0 so

x = 0 or 10x - 22 = 0 which makes

x equal to $\frac{22}{10}=2.2$

So x = 2.2 and y = 22.

7 0

2 years ago

PLEASE HELP ME WITH NUMBER 11, WORTH 15 POINTS!!! AAAAA

malfutka [58]

Answer: 43.4

Step-by-step explanation: if it was dilated by a bigger number than 1 then it’s goin to have a bigger area and in this case it was dilated by

4 2/3 so you multiply the area by 4 2/3 to round your answer to the nearest tenth and u get 43.4

6 0

2 years ago

8090 [49]

Answer:

James bought 11 good tickets and 5 bad tickets.

Step-by-step explanation:

Given that:

Cost of each good ticket = $8

Cost of each bad ticket = $5

Total amount spent = $113

Total tickets bought = 16

Let,

x be the number of good tickets bought

y be the number of bad tickets bought

x+y=16 Eqn 1

8x+5y=113 Eqn 2

Multiplying Eqn 1 by 5

5(x+y=16)

5x+5y=80 Eqn 3

Subtracting Eqn 3 from Eqn 2

(8x+5y)-(5x+5y)=113-80

8x+5y-5x-5y=33

3x=33

Dividing both sides by 3

$\frac{3x}{3}=\frac{33}{3}\\x=11$

Putting x=11 in Eqn 1

11+y=16

y=16-11

y=5

Hence,

James bought 11 good tickets and 5 bad tickets.

3 0

2 years ago