A. disconformity. I hope i helped you.
Answer:
0.1460
Explanation:
Total population size= 411 + 911 + 800 = 2122
Let's assume that the population is in Hardy Weinberg Equilibrium.
Under these conditions, frequency of recessive allele (a)= 911 x 2 + 800 / 2122 x 2 = 2622/4244= 0.6178
.
This is because each homozygous recessive genotype has two copies of the recessive allele while each heterozygous dominant genotype has one copy of the recessive allele.
For this population to be under Hardy Weinberg Equilibrium, frequency of dominant allele (A) = 1- 0.6178= 0.3822
Frequency of homozygous dominant genotype (AA) = 0.1460
If the 2 alleles are the equal, the character is homozygous for that allele. If the alleles are different, the character is heterozygous.
When a populace is in Hardy-Weinberg equilibrium for a gene, it isn't always evolving, and allele frequencies will live the equal throughout generations. There are 5 fundamental Hardy-Weinberg assumptions: no mutation, random mating, no gene flow, limitless populace size, and no selection.
To "fix" an allele method that the allele is gift at a frequency of 1.0, so all people withinside the populace have the equal allele at a locus.
To learn more about allele, click here:
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Answer:
Fimbriae
Explanation:
The fimbria is a type of pilus possessed by some bacteria (Gram positive or negative) specially designed for attachment to surfaces or to neighbouring cells.
<em>Pili are generally thread-like or hair-like outgrowths on the surface of bacteria or other prokaryotic cells. While some function as structures for attachment are often referred to as fimbriae, some function by stabilizing mating bacteria during conjugation process.</em>
Answer:
virtual and erect
behind the mirror
the size of the image is equal to the size of the object
laterally inverted image
Explanation:
