Answer:
It must restate the question.
All of them, they are all very important factors to test for the identifying
Answer:
<u>Part A</u> : 70 secondary oocytes will be formed.
<u>Part B</u> : 70 first polar bodies will be formed.
<u>Part C</u> : 70 ootids will be formed.
Explanation:
During oogenesis growth maturation of a single oogonium produces one primary oogonium.
the primary oogonium then undergoes meiosis -1 and produces one secondary oocyte and first polar body.
The secondary oocyte then undergoes meiosis - 2 and forms an ootid and second polar body.
The ootid then differentiates into the ovum.
As in the above scenario , 70 primary oocytes are present , they undergo meiosis-1 and produces 70 secondary oocytes and 70 first polar bodies. Hence answers of part A and B is 70.
As 70 secondary oocytes are formed , they undergo meiosis -2 and forms 70 ootids which then differentiate in 70 ovums.
Answer:
range from wings in flying animals like bats, birds, and insects, to fins in animals like penguins and fish, plants and other organisms can also demonstrate analogous structures such as sweet potatoes, which have the same function of food storage
If from the low tide to the high tide there was a break of 6h and 4m than the next tides will happen at the same rate:
8:35 + 6:04 = 14:39 = next low tide.
14:39 + 6:04 = 20:43 = next high tide.
Note that two same tides occur about 12h to 12h and 25m apart, and that is the case here:
14:39 - 2:31 = 12:08 hours apart
20:42 - 8:35 = 12:07 hours apart.
Hope it helped,
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