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posledela
3 years ago
9

An arithmetic sequence has a first term of 3 and a fifth term of 31 what is it’s second term

Mathematics
2 answers:
atroni [7]3 years ago
7 0

Answer:10

Step-by-step explanation:

Adds 7 each time

mrs_skeptik [129]3 years ago
6 0

31 - 3 = 28

Going from first term to fifth term is 4 increases.

28 ÷ 4 = 7

This means we have a common difference of 7.

Sequence is 3, 10, 17, 24, 31

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2÷628 this is my QUESTION what is the answer
Whitepunk [10]

Answer:

314 is the correct answer

Step-by-step explanation:

314 is the correct amswer to 628 ÷ 2, however, the answer to 2 ÷ 628 is invalid and would need to be simplified.

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Based on the polynomial remainder theorem, what is the value of the function when x=−6 ?
Vaselesa [24]
ANSWER

f( - 6) =  10


EXPLANATION

The given function is
f(x) =  {x}^{4}  + 8 {x}^{3}  + 10 {x}^{2}  - 7x + 40

According to the remainder theorem,

f( - 6) = R
where R is the remainder when
f(x)

is divided by
x + 6


We therefore substitute the value of x and evaluate to obtain,

f( - 6) =  { (- 6)}^{4}  + 8 {( - 6)}^{3}  + 10 { (- 6)}^{2}  - 7( - 6)+ 40




f( - 6) =  1296 + 8 ( - 216) + 10 (36) - 7( - 6)+ 40




f( - 6) =  1296  - 1728 + 360  + 42+ 40



This will evaluate to,


f( - 6) =  10


Hence the value of the function when
x =  - 6

is
10



According to the remainder theorem,
10
is the remainder when

f(x) =  {x}^{4}  + 8 {x}^{3}  + 10 {x}^{2}  - 7x + 40
is divided by
x + 6
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