Answer:
(n-1) / 2
Step-by-step explanation:
We have that the sum has the form of:
Sn = n / 2 [2 * a + (n-1) * d]
we compute the terms of a and d
a = 1 - 1 / n
a = (n - 1) / n
, that is, the first term, in the case d is the subtraction between the second and the first term, thus:
d = 1 - 2 / n - (1 - 1 / n)
d = 1 - 2 / n - 1 + 1 / n
d = - 1 / n
now if replacing these values:
Sn = n / 2 * [2 * (n - 1) / n + (n-1) * (- 1 / n)
Sn = n / 2 * [2 * (n-1) - (n-1)] / n
Sn = 1/2 * (n-1)
Therefore, the value of that sum is (n-1) / 2
Answer:
Number of fish in 2006 = 845 fishes (Approx.)
Step-by-step explanation:
Given;
Number of fish in 2000 = 1,150 fishes
Decreasing rate = 5% per year
Find:
Number of fish in 2006
Computation:
Exponential decay function:
F = P[1-r]ⁿ
Number of year = 2006 - 2000
Number of year = 6 year
Number of fish in 2006 = 1,150[1-5%]⁶
Number of fish in 2006 = 1,150[1-0.05]⁶
Number of fish in 2006 = 1,150[0.95]⁶
Number of fish in 2006 = 1,150[0.735]
Number of fish in 2006 = 845.25
Number of fish in 2006 = 845 fishes (Approx.)
1 stack of nickels is S=45gm; given that there are 9 nickels on each stack you can
divide the mass of the stack(
45)
by the
number of nickels in a stack(
9) to
find the
mass of 1 single
nickel
<u>5gm = 1 nickel</u>
G[f(-1)]
-2x[3-x(-1)]
-2x[-3-x]
6x-x
5x
Answer:
i feel like you need 76 from the 87
Step-by-step explanation:
