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2 years ago

A square originally starts with an area of 64 cm2.

Mathematics

2 answers:

faust18 [17]2 years ago

6 0

Answer:

100 cm2

Step-by-step explanation:

If the area is 64 cm2 that means that the side is 8 cm (square root of 64 is 8)

8 increased by 2 = 10

area 10x10 = 100 cm2

Radda [10]2 years ago

5 0

Answer:

the answer is 100cm²

since originally is 64 cm²

so square root of 64 is 8 cm.

after you get 8cm you get,

8+2 = 10cm (a side of square)

and then to find a new area you get,

10 × 10 = 100 cm²

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Which sum or difference identity would you use to verify that cos (180° - q) = -cos q?

Phantasy [73]

Answer:

$\cos (a-b)=\cos a \cos b+\sin a \sin b$

Step-by-step explanation:

Given : $\cos (180^{\circ}-q)=-\cos q$

We have to write which identity we will use to prove the given statement.

Consider $\cos (180^{\circ}-q)=-\cos q$

Take left hand side of given expression $\cos (180^{\circ}-q)$

We know

$\cos (a-b)=\cos a \cos b+\sin a \sin b$

Comparing , we get, a= 180° and b = q

Substitute , we get,

$\cos (180^{\circ}-q)=\cos 180^{\circ} \cos (q)+\sin q \sin 180^{\circ}$

Also, we know $\sin 180^{\circ}=0$ and $\cos 180^{\circ}=-1$

Substitute, we get,

$\cos (180^{\circ}-q)=-1\cdot \cos (q)+\sin q \cdot 0$

Simplify , we get,

$\cos (180^{\circ}-q)=-\cos (q)$

Hence, use difference identity to prove the given result.

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marishachu [46]

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