1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
denis23 [38]
3 years ago
9

Work the following financial transactions. Your station charges $15.95 for an oil change. As a promotion you sell six coupons fo

r oil changes for $80. What percentage discount are you offering for customers who purchase the 6-coupon book? Discount (to the nearest tenth) = _____.
Mathematics
2 answers:
Galina-37 [17]3 years ago
6 0

Answer:

Discount percentage is 16.4% for the customers who purchase 6- coupon book .

Step-by-step explanation:

Formula

Discount\ percentage = \frac{Discount\times 100}{Original charge of the oil change for 6 times}

As given

Your station charges $15.95 for an oil change.

Original charge of the oil change for 6 times = 6 × Original charge for oil change .

                                                                          = 6 × 15.95

                                                                          = $ 95.7

As a promotion you sell six coupons for oil changes for $80.

Discount = Original charge of the oil change for 6 times - Charge by six coupons for oil changes .

               = $95.7 - $80

               = $ 15.7

Putting all the values in the above

Discount\ percentage = \frac{15.7\times 100}{95.7}

Discount\ percentage = \frac{15700\times 10}{957\times 10}

Discount\ percentage = \frac{15700}{957}

Discount percentage = 16.4%

Therefore the discount percentage is 16.4% for the customers who purchase 6- coupon book .

Stells [14]3 years ago
4 0
About 16%. Rounded to the nearest tenth is 20%
You might be interested in
TOPIC: AREA OF COMPOSITE FIGURES!!... HELLO!! :) CAN U PLEASE HELP ME WITH THIS PROBLEM? I WILL GIVE YOU BRAINLIEST AND A THANKS
alexandr402 [8]

Answer:

ppppppppppppppppppppppppppppppppppppppppppp

Step-by-step explanation:

i did this 4 points

8 0
2 years ago
The speed of the current in a river is 6mph. A ferry operator who works that part of the river is looking to buy a new boat for
Nezavi [6.7K]
Hello,
Please, see the attached files.
Thanks.

4 0
3 years ago
AE is an angle bisector of BAC if the measure of BAE = x + 30 and masure of angle EAC = 3x-10 determine Measure of angle EAC
TEA [102]
The measure of angle EAC is equivalent to 50 degrees.
5 0
2 years ago
4. *Each pair of polygons is similar. Find the value of x.
torisob [31]

Step-by-step explanation:

since both objects and sides are similar, you can set each side equal, then you cross multiply, and do subtraction, then find x.

3 0
3 years ago
Mrs.Cheng has $18 deducted monthly from checking account for her gym membership. What integer represents the change in her accou
Vikki [24]
First you would have to multiply $18 (The cost for each month) and 12 (the number of months in a year) and the answer would be 216
So she deducts 216 a year, so the answer would have to be negative

The final answer is -216
4 0
3 years ago
Other questions:
  • How many terms are there in the expression 2x - 5y + 3 + x? <br> 3<br> 4<br> 5<br> 6
    14·2 answers
  • What is -4 3/4+2 1/2
    8·1 answer
  • What is the value of y in the equation 5x + 2y = 20, when x = 0.3?
    5·2 answers
  • When g(x) is divided by x + 4 the remainder is 0. Given g(x)=x^4+3x^3-6x+8 which conclusion about g(x) is true?
    10·1 answer
  • I need help on this question.
    9·2 answers
  • What is the length of DE in the right triangle below
    9·1 answer
  • Quadrilateral A B C D, the measure of, angle A, angle B, angle C, angle D are a ratio of 1:2:3:4, respectively. Find the measure
    13·1 answer
  • In a basketball game, Alison made 6 of 13 free shots.
    12·2 answers
  • Find the LCM of ;<br>(1+4x+4x2-16x) and (1+2x-8x3-16x4)​
    12·1 answer
  • I need help!!!!!!!!!!!​
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!