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3 years ago

Solve 9x² - 6x + 1 = 0 using the Quadratic Formula.

Mathematics

1 answer:

andrezito [222]3 years ago

7 0

Answer:1/3 i dont know if this is right i just kindly copied the guy on top

Step-by-step explanation:

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There are 850 Douglas fir and Ponderosa pine trees in a section of forest bought by Karamazov Logging Co. The company paid an av

ki77a [65]

Answer:

350 Douglas fir, 500 Ponderosa pine

Step-by-step explanation:

Let f = the number of fir trees

and p = the number of pine trees.

Then, we have two conditions:

(1) f + p = 850

(2) 300f + 225p = 217 500

(3) p = 850 -f Subtracted f from each side of (1)

(4) 300f + 225(850 - f) = 217 500 Substituted (3) into (3)

300f + 191 250 - 225f = 217 500 Distributed 225

75f + 191 250 = 217 500 Distributed the 7

75f = 26 250 Subtracted 191 250 each side

(5) f = 350

350 + p = 850 Substituted (5) into (1)

p = 500 Subtracted 350 from each side

The company bought 350 fir trees and 500 pine trees.

Check:

(1) 350 + 500 = 850 (2) 300 × 350 + 225 × 500 = 217 500

850 = 850 105 000 + 112 500 = 217 500

217 500 = 217 500

OK.

8 0

3 years ago

Evaluate 5a-2b if a=3, and b=2

Anna71 [15]

Answer:

Step-by-step explanation:

4 0

3 years ago

The endpoints of a diameter of a circle are (6,2) and (−2,5) . What is the standard form of the equation of this circle?

Paul [167]

Answer:

The standard form of the given circle is

$(x-2)^2+(y-\frac{7}{2})^2=73$

Step-by-step explanation:

Given that the end points of a diameter of a circle are (6,2) and (-2,5);

Now to find the standard form of the equation of this circle:

The center is (h,k) of the circle is the midpoint of the given diameter

midpoint formula is $M=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

Let $(x_{1},y_{1})$ and $(x_{2},y_{2})$ be the given points (6,2) and (-2,5) respectively.

$M=(\frac{6-2}{2},\frac{2+5}{2})$

$M=(\frac{4}{2},\frac{7}{2})$

$M=(2,\frac{7}{2})$

Therefore the center (h,k) is $(2,\frac{7}{2})$

now to find the radius:

The diameter is the distance between the given points (6,2) and (-2,5)

$d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

$=\sqrt{(-2-6)^2+(5-2)^2}$

$=\sqrt{(-8)^2+(3)^2}$

$=\sqrt{64+9}$

$=\sqrt{73}$

Therefore the radius is $\sqrt{73}$

i.e., $r=\sqrt{73}$

Therefore the standard form of the circle is

$(x-h)^2+(y-k)^2=r^2$

Now substituting the center and radiuswe get

$(x-2)^2+(y-\frac{7}{2})^2=(\sqrt{73})^2$

$(x-2)^2+(y-\frac{7}{2})^2=73$

Therefore the standard form of the given circle is

$(x-2)^2+(y-\frac{7}{2})^2=73$

5 0

3 years ago

A chalkboard has an area of 35.8 ft a smaller chalkboard is 0.7 times that size what is the area of the smaller chalkboard

Elenna [48]

The smaller chalkboard would be 25.06 ft

3 0

3 years ago

Which answer is equal to (f - g) (-5)

Marina CMI [18]

f(5)= 2+5 = 7
g(5)= 5^2+5 = 25 +5 = 30

(f - g) (-5) = 7 - 30 = -23

answer is D.-23

6 0

3 years ago