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3 years ago

Factorise y^2 - 16 (y squared)

Mathematics

2 answers:

cricket20 [7]3 years ago

8 0

$y^2-16=y^2-4^2=(y-4)(y+4)\\\\\text{used}\ a^2-b^2=(a-b)(a+b)$

Mila [183]3 years ago

3 0

Sqrt(y^2) = y
sqrt(16) = 4
-4y + 4y = 0
The answer is
(y-4)(y+4)

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A triangle with vertices at A(0,0), B(0,4), and C(6,0) is dilated to yield a triangle with vertices at A(0,0), (B(0,10), and C (

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The required scale factor for the dialed triangle is given by SF= 6.28

A triangle with vertices at A(0,0), B(0,4), and C(6,0) is dilated to yield a triangle with vertices at A(0,0), (B(0,10), and C (C(15,0).

<h3>What is scale factor?</h3>

The scale factor is defined as the ratio of modified change in length to the original length.

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For this step, we are going to let:

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We're going to use the distributive party again, but a slightly different version that's almost the same as first:

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$y^2+3y+xy+x+2$

This should be your answer. Let me know if you need any clarifications, thanks!

~ Padoru

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