- The kind of curve obtained is linear.
- The relationship between the variables is direct variation.
- After 4.5 seconds, I expect the velocity to be equal to 140 ft/s.
- The amount of time required for the object to attain a speed of 100 ft/s is 3.2 seconds.
<h3>What is a graph?</h3>
A graph can be defined as a type of chart that's commonly used to graphically represent data on both the horizontal and vertical lines of a Cartesian coordinate, which are the x-axis and y-axis.
In this exercise, you're required to plot a graph for the data (velocity and time) recorded for an object that is falling from rest.
Based on the graph for the data (see attachment), we can logically deduce the following points:
- The kind of curve obtained is linear.
- The relationship between the variables is direct variation.
- After 4.5 seconds, I expect the velocity to be equal to 140 ft/s.
- The amount of time required for the object to attain a speed of 100 ft/s is 3.2 seconds.
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Complete Question:
Plot a graph for the following data recorded for an object falling from rest
a. What kind of a curve did you obtain?
b. What is the relationship between the variables?
c. What do you expect the velocity to be after 4.5 s?
d. How much time is required for the object to attain a speed of 100 ft/s?
Answer:
x = 24
Step-by-step explanation:
I checked and made sure the answer was correct.
Hope this helps!
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Function B best models the researcher's data because it passes through most of the points.
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
A graph of best fit can be determined by drawing a straight line or curve on a scatter plot so that the number of points above the line and below the line is about equal and the graph passes through most of the points.
Function B best models the researcher's data because it passes through most of the points.
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First we should figure out how much over the weight limit the passengers are. We can find this by 750-450 which is 300. The amount of weight that needs to get off the elevator is 300 kilograms. Then, we know that each passenger weighs 70 kilograms. We can represent this as 70p.The inequality is 70p \geq 300. Then we can solve by dividing both sides of the inequality by 70. We get p \geq 4.28... Since people only come in whole numbers, and it has to be greater than 4.28, the number of excess passengers is 5.
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L=Lim tan(x)^2/x x->0
Since both numerator and denominator evaluate to zero, we could apply l'Hôpital rule by taking derivatives.
d(tan^2(x))/dx=2tan(x).d(tan(x))/dx = 2tan(x)sec^2(x)
d(x)/dx = 1
=>
L=2tan(x)sec^2(x)/1 x->0
= (2(0)/1^2)/1
=0/1
=0
Another way using series,
We know that tan(x) = x+x^3/3+2x^5/15+.....
then tan^2(x), using binomial expansion gives
x^2+2*x^4/3+.... (we only need two terms)
and again apply l'Hôpital's rule, we have
L=d(x^2+2x^4/3+...)/d(x) = (2x+8x^3/3+...)/1
=0 as x->0
