Answer:
Infinite pairs of numbers
1 and -1
8 and -8
Step-by-step explanation:
Let x³ and y³ be any two real numbers. If the sum of their cube roots is zero, then the following must be true:
![\sqrt[3]{x^3}+ \sqrt[3]{y^3}=0\\ \sqrt[3]{x^3}=- \sqrt[3]{y^3}\\x=-y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%2B%20%5Csqrt%5B3%5D%7By%5E3%7D%3D0%5C%5C%20%5Csqrt%5B3%5D%7Bx%5E3%7D%3D-%20%5Csqrt%5B3%5D%7By%5E3%7D%5C%5Cx%3D-y)
Therefore, any pair of numbers with same absolute value but different signs fit the description, which means that there are infinite pairs of possible numbers.
Examples: 1 and -1; 8 and -8; 27 and -27.
<span>Every point went up 4 units and left 3 units.
</span><span>Point X on the triangle moved up 4 and left 3.
That formed a right triangle with legs 4 and 3.
The distance point X moved to point X', d, is the hypotenuse of the right triangle.
</span><span>Using the Pythagoras Theorem
</span><span><span>3^2</span>+<span>4^2</span>=<span>d^2
d = 5
</span></span>
Answer:
what may be true
Step-by-step explanation:
i just took the test and got the answer correct, i hope this helps.
