A) The given equation has no solution. The absolute value cannot be negative, but must be -9 in order for the equation to be satisfied.
b) |x -7| = 2 . . . . . . . the equation
Solution 1:
-2 = x -7
5 = x . . . . . . add 7
Solution 2
x -7 = 2
x = 9 . . . . . . add 7
The two numbers are {5, 9}
If x- 7 = 14 then X = 21. so 21-2= 19. :)
The quotient is x^3 + 4x^2 -x + 1.
Solution:
By polynomial grid division, we start by the divisor 3x + 10 placed on the column headings.
3x 10
x^3 3x^4
We know that 3x^4 must be in the top left which means that the first row entry must be x^3. So the row and column multiply to 3x^4. We use this to fill in all of the first row, multiplying x^3 by the terms of the column entries.
3x 10
x^3 3x^4 10x^3
4x^2
We now got 10x^3 though we want 22x^3. The next cubic entry must then be 12x^3 so that the overall sum is 22x^3.
3x 10
x^3 3x^4 10x^3
4x^2 12x^3
Now we have 40x^2, so the next quadratic entry must be -3x^2 so that the overall sum is 37x^2.
3x 10
x^3 3x^4 10x^3
4x^2 12x^3 40x^2
-x -3x^2 -10x
This time we have -10x, so the next linear entry must be 3x so that the overall sum is 7x.
3x 10
x^3 3x^4 10x^3
4x^2 12x^3 40x^2
-x -3x^2 -10x
1 3x 10
The bottom and final term is 10, which is our desired answer. Therefore, we can now read the quotient off the first column:
3x^4+22x^3+37x^2-7x+10 / 3x + 10 = x^3 + 4x^2 -x + 1
301 minus 200? If so, that is 101
