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olga nikolaevna [1]
3 years ago
10

A bag contains 5 red marbles, 7 blue marbles and 8 green marbles. If three marbles are drawn out of the bag, what is the probabi

lity, to the nearest 10th of a percent, that all three marbles drawn will be green?
Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
4 0

Answer:

8/20 or 4 percent

Step-by-step explanation:

BigorU [14]3 years ago
4 0

Answer:

4.9%

Step-by-step explanation:

There are a total of 20 marbles.

The probability that the first marble is green is 8/20.

The probability that the second marble is green is 7/19.

The probability that the third marble is green is 6/18.

The total probability is:

P = (8/20) (7/19) (6/18)

P ≈ 0.049

The probability is 4.9%.

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hichkok12 [17]
In this problem you would set these two equations equal to each other.
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After this you would simplify the equation to isolate x (being the number of toppings you put on the pizzas) 

$8+ 1.50x =$10+ 1x
-8              -8
----------------------------
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--------------------------- 
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1:4

Step-by-step explanation:

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