Answer:
If i have three moles of a gas at a pressure of 5.6 atm and a volume of 3 liters, what is the temperature ?
We have the following data:
n (number of moles) = 3 moles
P (pressure) = 5.6 atm
V (volume) = 12 L
T (temperature) = ? (in Kelvin)
R (gas constant) = 0.082 atm.L / mol.K
We apply the data above to the Clapeyron equation (gas equation), let's see:
Answer:
The temperature is approximately 205 Kelvin
Answer:
1. adjacent: ∠ACB and ∠BCD.
vertical: ∠ACB and ∠ECD
Step-by-step explanation:
Answer:
Step-by-step explanation:
Equation: 
Jalil says it is not possible to isolate x because x has a different unknown coefficient.
Victoria t. Victoria believes there is a solution
Solving the equation:
So, this shows x can be isolated .
Victoria was right .
It was not possible to isolate x if the coefficients of x would be same .
But in the given equation the coefficients of x are not same .
So, Victoria is right.
Answer: The solution is (4, -4)
Answer:
Step-by-step explanation:
Factoring will reveal the solution. So we divide the equation by the greatest common factor of the terms and use that factor as the coefficient. In this case the greatest common factor is just x.
2x^2+5x
x(2x+5) so the equation will equal zero when either of those expressions is zero because zero times anything is zero. x=0 and x=-5/2
