Answer:
Solution:
The formula to find the perimeter of the quadrilateral = sum of the length of all the four sides.
Here the lengths of all the four sides are 5 cm, 7 cm, 9 cm and 11 cm.
Therefore, perimeter of quadrilateral = 5 cm + 7 cm + 9 cm + 11 cm
= 32 cm
Answer:
The scale is 1:200
Step-by-step explanation:
On the plan we have the drawing as 6 cm
In real representation, we have the distance as 12 m
Firstly we have to convert to same unit
In this case, we use the cm for convenience
Mathematically, 100 cm is 1 m
Thus, 12 m
will be 12 * 100 = 1,200 cm
So, we have the ratio as;
6 cm : 1,200 cm
and that is 1:200 (since 6/1200 = 1/200 and in ratio form, we have that as 1:200)
32= 4x
That would be the equation and x would then be 8
hope this helps
Answer:
0.332
Step-by-step explanation:
given series
1/4, 1/16,1/64.1/256
this is geometric series
where common ratio r is given by
nth term/ (n-1)th term
let the second term is nth term and first term is (n-1)th term
r = 1/16 / (1/4) = 1/4
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sum of series is given by
a (1-r^n)/1-r
where a is first term
n is the number of terms
r is the common ration
___________________________________________
in the given series
1/4, 1/16,1/64.1/256
a = 1/4
r = 1/4
n = 4
thus ,
sum = 1/4(1-(1/4)^4)/ (1-1/4)
sum = 1/4(1-(1/256)/(4-1)/4
sum = 1/4((256-1)/256 / 3/4
1/4 in numerator and denominator gets cancelled
sum =( 255/256*3) = 255/768 = 0.332
Thus, sum of series is 0.332.
h(x) = 3 * (2)^x
Section A is from x = 1 to x = 2
h(1) = 3 * (2)^1 = 3 * 2 = 6
h(2) = 3 * (2)^2 = 3 * 4 = 12
so
the average rate of change = (12 - 6)/(2 - 1) = 6
Section B is from x = 3 to x = 4
h(3) = 3 * (2)^3 = 3 * 8 = 24
h(4) = 3 * (2)^4 = 3 * 16 = 48
so
the average rate of change = (48 - 24)/(4 - 3) = 24
Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points)
the average rate of change of section B is 24 and the average rate of change of section A is 6
So 24/6 = 4
The average rate of change of Section B is 4 times greater than the average rate of change of Section A
It's exponential function, not a linear function; so the rate of change is increasing.
