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3 years ago

6

plz help !! very URGENT!!! first to answer will be mark as the brainyest!! also explain the steps that you took and which letter

is the answer.

1 answer:

hammer [34]3 years ago

5 0

Your answer is c: f=2 1/2 c

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Calculate dy/dxif y = 4x3 + 3x2 + 2.

Elena-2011 [213]

The answer is
<span>A. 12x2 + 6x

solution
</span><span>y = 4x3 + 3x2 + 2
</span><span>y'(x) = 12x^2 + 6x

</span>

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3 years ago

If cost 5:50 per Hour to rent a pair of ice skates for Up to 2 hours. After 2 hours, the rental cost per hour decreases to 2:50.

Zielflug [23.3K]

16$

5.50 *2 for the first 2 hours

2.50 *2 for 2 hours after the decrease of prices

11 + 5

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3 years ago

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I need the corresponding letters on the equation.<br> A=<br> B=<br> C=<br> D=<br> E=<br> F=<br> G=

REY [17]

Answer:

A = 3

B = 1

C = 2

D = 10

E = 2

F = Not listed

G = 1

Step-by-step explanation:

$\sqrt[3]{270x^5y^7} =\sqrt[3]{27*10x^5y^7}=3xy^2\sqrt[3]{10x^2y}$

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3 years ago

Which expression should you simplify to find the 90% confidence interval,

bogdanovich [222]

Answer:

$0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.2870.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613$

we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

Step-by-step explanation:

The estimated proportion of interest is $\hat p=0.45$

We need to find a critical value for the confidence interval using the normla standard distributon. For this case we have 95% of confidence, then the significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ .

And the critical value is: $z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the true population proportion is interest is given by this formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

Replacing the values provided we got:

$0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287\\\\0.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613$

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

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3 years ago

On a given morning the temperature was 71°F. The temperature dropped 5°F and then rose 8°F. How much does the temperature need t

professor190 [17]

Answer:

Step-by-step explanation:

Temperature needs to fall by 3 degrees

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3 years ago

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