complete question:
The sum of the digits of a two-digit numeral is 8. If the digits are reversed, the new number is 18 greater than the original number. How do you find the original numeral?
Answer:
The original number is 10a + b = 10 × 3 + 5 = 35
Step-by-step explanation:
Let
the number = ab
a occupies the tens place while b occupies the unit place. Therefore,
10a + b
The sum of the digits of two-digits numeral
a + b = 8..........(i)
If the digits are reversed. The reverse digit will be 10b + a. The new number is 18 greater than the original number.
Therefore,
10b + a = 18 + 10a + b
10b - b + a - 10a = 18
9b - 9a = 18
divide both sides by 9
b - a = 2...............(ii)
a + b = 8..........(i)
b - a = 2...............(ii)
b = 2 + a from equation (ii)
Insert the value of b in equation (i)
a + (2 + a) = 8
2a + 2 = 8
2a = 6
a = 6/2
a = 3
Insert the value of a in equation(ii)
b - 3 = 2
b = 2 + 3
b = 5
The original number is 10a + b = 10 × 3 + 5 = 35
We are asked to solve for the incremental net income from reworking the phones.
Number of items = 1000
Production Cost = 1000*$60 = $60,000
Salvage value = 1000*$30 = $30,000
Rework Cost = 1000 *80 = $80,000
Price when resold = 1000 * $120 = $120,000
Incremental Net = $120,000 + $30,000 - $60,000 -$80,000
Incremental Net = $10,000
The answer is $10,000.
Answer:
value of x = 26
value of y = 26 \|2
( 26 root 2 )
Step-by-step explanation:
here's the solution : -
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and
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Answer:
(fog)(x) = 4x - 7
Step-by-step explanation:
f(x) = 2x-1 and g(x) = 2x-3;
(fog)(x) = f(g(x)
= f(2x - 3) = 2(2x - 3) - 1
= 4x - 6 - 1
= 4x - 7
