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2 years ago

Problem 1

Mathematics

1 answer:

anyanavicka [17]2 years ago

4 0

Answer:

1) both lights will blink at the same time every 20 seconds

2)Both lights will blink at the same time every 36 seconds

3) How to determine when 2 lights will blink together is that you must find the least common factor (LCM) of both numbers and when both hit the same number then that is when both lights blink at the same time.

Step-by-step explanation:

For example for number 1 we have 4 and 5 seconds when the lights blink

4: 4, 8, 12, 16, 20...

5: 5, 10, 15, 20...

we see that the LCM factor is 20 and that is when both lights will hit at the same time.

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Luna ordered a package from Amazon. Her package weighed 576 ounces when it was delivered to her door step. Her brother also orde

ladessa [460]

Answer:

Step-by-step explanation:

Luna's weight = 576 oz

Her bothers package is 1/100 times the weight of hers.

1/100 * 576 = 5.76 oz

Answer to the second part, about 1/2 an oz

1/1000 * 576 = 0.576 oz.

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3 years ago

State the horizontal asymptote of the rational function.<br> f(x) = x^2 + 9x-9/x-9

dusya [7]

Answer:

no horizontal asymptote

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3 years ago

Find the variation constant and an equation of variation where y varies directly as x and y=24 when x=3.

Kay [80]

Answer:

Step-by-step explanation:

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3 years ago

A circular pen has an area of 64<img src="https://tex.z-dn.net/?f=%20%20%5Cpi%20" id="TexFormula1" title=" \pi " alt=" \pi " a

Allisa [31]

What we know:
shape is circular
Area=64π yr²
Area=πr²
circumference=2πr

In order to find circumference we need r=radius. We can use the area to find r by solving for r using substitution of the information we know above.

Area=πr²
64π=πr² substitution
64π/π=π/πr² multiplicative inverse
64=r²
√64=√r² properties of radicals
8=r We would get two solutions, a positive and negative one but we will only use the positive solution since radius is positive

Circumference=2πr
C=2π(8)=16π yards

7 0

3 years ago

Read 2 more answers

The roots of 2x^2-3x=4 are a and b. Find the simplest quadratic equation which has roots 1/a and 1/b

Tju [1.3M]

Find the roots

solve
we use hmm, completing the suare
2(x²-1.5x)=4
divide both sides by 2
x²-1.5x=2
take 1/2 of linear coeiftn and square it
-1.5/2=-0.75, (-0.75)²=0.5625
add that to both sides
x²-1.5x+0.5625=2+0.5625
factor perfect squaer trinomial
(x-0.75)²=2.5625
square root both sides, remember to take positive and negative square roots
x-0.75=+/-√2.5625
add 0.75 to both sides
x=0.75+/-√2.5625

the roots are x=0.75+√2.5625 and x=0.75-√2.5625

1/a and 1/b
1/(0.75+√2.5625) and 1/(0.75-√2.5625)

if the roots of a quadratic equation are r1 and r2 then it factors to
(x-r1)(x-r2)
so then we can factor our equation to be
$(x-\frac{1}{0.75+\sqrt{2.5625}})(x-\frac{1}{0.75-\sqrt{2.5625}})$

if we were to try and expand it, we would get
x²+0.75x-0.5
that's the simpliest equation with roots 1/a and 1/b where a and b are he roots of 2x²-3x=4

x²+0.75x-0.5 is answer

8 0

3 years ago