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1 year ago

Problem 1

Mathematics

1 answer:

anyanavicka [17]1 year ago

4 0

Answer:

1) both lights will blink at the same time every 20 seconds

2)Both lights will blink at the same time every 36 seconds

3) How to determine when 2 lights will blink together is that you must find the least common factor (LCM) of both numbers and when both hit the same number then that is when both lights blink at the same time.

Step-by-step explanation:

For example for number 1 we have 4 and 5 seconds when the lights blink

4: 4, 8, 12, 16, 20...

5: 5, 10, 15, 20...

we see that the LCM factor is 20 and that is when both lights will hit at the same time.

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HELP. It costs $4.25 for one pound of roast beef and $3.70 for one pound of ham. How much will it cost to purchase 2.5 pounds of

tensa zangetsu [6.8K]

Answer:

it will cost $10.63 for 2.5 pounds of roast beef

$12.95 for 3.5 pounds of ham

Step-by-step explanation:

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1 year ago

The students at Midtown Middle school sold flowers as a fundraiser in September and October. In October, they charged $1.50 for

lions [1.4K]

In the question it is given that,

The students at Midtown Middle school sold flowers as a fundraiser in September and October. In October, they charged $1.50 for each flower

And the October price was a 20% increase of the September price.

Let the price of the flower in October be $x

So we have

$x+ \frac{20}{100}x = 1.50 \\ \frac{120x}{100} = 1.50 \\ x = \frac{1.50*100}{120} = 1.25$

So the price of the flower in Septembet is $1.25 .

7 0

2 years ago

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

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2 years ago

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Hope this helps! ;)

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2 years ago

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Mashcka [7]

I hope this helps you

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2 years ago