3 x 4 1/3 = ?? -- please help me

What does it mean if I say addition and multiplication are associative

ohaa [14]

Meaning you don't have to solve the equation in a certain order just left to right in order to find the answer unlike division and subtraction

4 0

3 years ago

What is the common difference in the arithmic sequence 30,27,24,21,18

vichka [17]

If you have two terms in a sequence, then a term decreased by the previous term=common difference

so
30 and 27

27 decreased by 30 is -3

the common differce is -3

6 0

2 years ago

In parallelogram HJKL if m∡HJK=110∘ find m∡JKL.

pav-90 [236]

Answer:

∠ JKL = 70°

Step-by-step explanation:

Consecutive angles in a parallelogram are supplementary , then

∠ JKL + ∠ HJK = 180°

∠ JKL + 110° = 180° ( subtract 110° from both sides )

∠ JKL = 70°

7 0

2 years ago

Determine whether or not F is a conservative vector field. If it is, find a function f such that F = ∇f. (If the vector field is

Elis [28]

In order for F to be conservative, there must be a scalar function f such that the gradient of f is equal to F. This means

$\dfrac{\partial f}{\partial x}=3x^2-2y^2$

$\dfrac{\partial f}{\partial y}=4xy+4$

Integrate both sides of the first equation with respect to x :

$f(x,y)=x^3-2xy^2+g(y)$

Differentiate both sides with respect to y :

$\dfrac{\partial f}{\partial y}=-4xy+\dfrac{\mathrm dg}{\mathrm dy}=4xy+4\implies\dfrac{\mathrm dg}{\mathrm dy}=8xy+4$

But we assume g is a function of y, which means its derivative can't possibly contain x, so there is no scalar function f whose gradient is F. Therefore F is not conservative.

8 0

3 years ago

Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 47.3 m

Marta_Voda [28]

Answer:

$\bar X = \frac{2276}{48}=47.417$

If we compare this value with the 47.3 proposed we have the following error

$Error = \frac{|Actual-real|}{real}*100 = \frac{|47.417-47.3|}{47.3}*100 =0.247\%$

The computed mean is close to the actual mean because the difference between the means is less than 5%.

Step-by-step explanation:

Assuming the following dataset:

Speed 42-45 46-49 50-53 54-57 58-61

Freq. 21 15 6 4 2

And we are interested in find the mean, since we have grouped data the formula for the mean is given by:

$\bar X = \frac{\sum_{i=1}^n x_i f_i}{\sum_{i=1}^n f_i}$

And is useful construct a table like this one:

Speed Freq Midpoint Freq*Midpoint

42-45 21 43.5 913.5

46-49 15 47.5 712.5

50-53 6 51.5 309

54-57 4 55.5 222

58-61 2 59.5 119

Total 48 2276

And the mean is given by:

$\bar X = \frac{2276}{48}=47.417$

If we compare this value with the 47.3 proposed we have the following error

$Error = \frac{|Actual-real|}{real}*100 = \frac{|47.417-47.3|}{47.3}*100 =0.247\%$

The computed mean is close to the actual mean because the difference between the means is less than 5%.

6 0

3 years ago