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omeli [17]
2 years ago
10

5) Original price of a CD: $17.00 Discount: 50%

Mathematics
1 answer:
NISA [10]2 years ago
4 0
Answer: 8.5
17/0.50 is 8.5
17-8.5
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What is the upper bound of the function f(x)=4x4−2x3+x−5?
inessss [21]

Answer:

(no global maxima found)

Step-by-step explanation:

Find and classify the global extrema of the following function:

f(x) = 4 x^4 - 2 x^3 + x - 5

Hint: | Global extrema of f(x) can occur only at the critical points or the endpoints of the domain.

Find the critical points of f(x):

Compute the critical points of 4 x^4 - 2 x^3 + x - 5

Hint: | To find critical points, find where f'(x) is zero or where f'(x) does not exist. First, find the derivative of 4 x^4 - 2 x^3 + x - 5.

To find all critical points, first compute f'(x):

d/( dx)(4 x^4 - 2 x^3 + x - 5) = 16 x^3 - 6 x^2 + 1:

f'(x) = 16 x^3 - 6 x^2 + 1

Hint: | Find where f'(x) is zero by solving 16 x^3 - 6 x^2 + 1 = 0.

Solving 16 x^3 - 6 x^2 + 1 = 0 yields x≈-0.303504:

x = -0.303504

Hint: | Find where f'(x) = 16 x^3 - 6 x^2 + 1 does not exist.

f'(x) exists everywhere:

16 x^3 - 6 x^2 + 1 exists everywhere

Hint: | Collect results.

The only critical point of 4 x^4 - 2 x^3 + x - 5 is at x = -0.303504:

x = -0.303504

Hint: | Determine the endpoints of the domain of f(x).

The domain of 4 x^4 - 2 x^3 + x - 5 is R:

The endpoints of R are x = -∞ and ∞

Hint: | Evaluate f(x) at the critical points and at the endpoints of the domain, taking limits if necessary.

Evaluate 4 x^4 - 2 x^3 + x - 5 at x = -∞, -0.303504 and ∞:

The open endpoints of the domain are marked in gray

x | f(x)

-∞ | ∞

-0.303504 | -5.21365

∞ | ∞

Hint: | Determine the largest and smallest values that f achieves at these points.

The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:

The open endpoints of the domain are marked in gray

x | f(x) | extrema type

-∞ | ∞ | global max

-0.303504 | -5.21365 | global min

∞ | ∞ | global max

Hint: | Finally, remove the endpoints of the domain where f(x) is not defined.

Remove the points x = -∞ and ∞ from the table

These cannot be global extrema, as the value of f(x) here is never achieved:

x | f(x) | extrema type

-0.303504 | -5.21365 | global min

Hint: | Summarize the results.

f(x) = 4 x^4 - 2 x^3 + x - 5 has one global minimum:

Answer: f(x) has a global minimum at x = -0.303504

5 0
3 years ago
Read 2 more answers
What is the slope of this line
kifflom [539]

Answer:

3/4

Step-by-step explanation:

We can find the slope from the two points given

m = (y2-y1)/(x2-x1)

   = (1- -2)/(2 - -2)

    = (1+2)/(2+2)

    = 3/4

8 0
3 years ago
Will give brainliest if this math question is answered correctly
solniwko [45]

Answer:  37 fruit pies+42 fruit juices=79 total items

(a) 37*1.65= $61.05

    42*1.36= $57.12

(b) Mr Sanchez's class earned more money.

(c) Mr. Sanchez's class earned $3.93 more than Mr. Kelly's class

    $61.05-$57.12= $3.93


Step-by-step explanation:


6 0
3 years ago
Find the diameter of a cirele with a circumference, c, of 27cm. HELP WILL GIVE BRAINLIST IF CORRECT ANSWER
Verdich [7]

Answer:

54

Step-by-step explanation:

The circumfirance is the diameter times 2

5 0
1 year ago
Consider U = {x|x is a negative real number}.
gizmo_the_mogwai [7]

Answer:

{x\ x e U and x has a negative square root} is an empty set.

Step-by-step explanation:

If x e U, x is a negative real number, and they don't have a square root (they don't have even roots). Their square roots are complex numbers, not real ones.

6 0
3 years ago
Read 2 more answers
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