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zheka24 [161]
3 years ago
7

Would like scatter plot image with line of best fit on the plot

Mathematics
1 answer:
dlinn [17]3 years ago
7 0

Just take it in co-ordinate pairs

  • (x,y)=(Arm span,Height)

Take two points

  • (58,60)
  • (41,40)

Slope:-

\\ \sf\longmapsto m=\dfrac{40-60}{41-58}

\\ \sf\longmapsto m=\dfrac{-20}{-17}

\\ \sf\longmapsto m=\dfrac{20}{17}

\\ \sf\longmapsto m\approx 1.2

Equation of line in point slope form

\\ \sf\longmapsto y-y_1=m(x-x_1)

\\ \sf\longmapsto y-60=1.2(x-58)

\\ \sf\longmapsto y-60=1.2x-69.6

\\ \sf\longmapsto 1.2x-y-9.6=0

  • Convert to slope intercept form y=mx+b

\\ \sf\longmapsto y=1.2x-9.6

Graph attached

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A rectangle has an area of 616 m² and a width of 22m. What is its length?
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Marrrta [24]

Answer:

Step-by-step explanation:

B(2,10); D(6,2)

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Rhombus all sides are equal.

AB = BC = CD =AD

distance = √(x2-x1)² + (y2- y1)²

As A lies on x-axis, it y-co ordinate = 0; Let its x-co ordinate be x

A(X,0)

AB = AD

√(2-x)² + (10-0)² = √(6-x)² + (2-0)²

√(2-x)² + (10)² =  √(6-x)² + (2)²

√x² -4x +4 + 100 =  √x²-12x+36 + 4

√x² -4x + 104 =  √x²-12x+40

square both sides,

x² -4x + 104 =  x²-12x+40

x² -4x - x²+ 12x = 40 - 104

             8x = -64

               x = -64/8

               x = -8

A(-8,0)

Let C(a,b)

M is AC midpoint

(-8+a/2, 0 + b/2)  = M(4,6)

     (-8+a/2, b/2)  = M(4,6)

Comparing;  

-8+a/2 = 4          ; b/2 = 6

  -8+a = 4*2       ; b = 6*2

  -8+a = 8          ; b = 12

        a = 8 +8

       a = 16

Hence, C(16,12)

6 0
3 years ago
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Elis [28]

Answer:

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ale4655 [162]

Answer:

It would be the first answer.

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