Answer: The amount of carbon-14 remaining after 4 years is 99.95 grams.
Step-by-step explanation:
Hi, to answer this question we simply have to substitute t=4 in the equation given and solve for c.
c= 100 (0.99988)^t
c =100 (0.99988)^4
c = 100 x 0.999520086
c= 99.95200864 ≅99.95 grams (rounded)
The amount of carbon-14 remaining after 4 years is 99.95 grams.
Feel free to ask for more if needed or if you did not understand something.
Answer:
(2,-2)
Step-by-step explanation:

Answer: 72.78% of the drivers are traveling between 70 and 80 miles per hour based on this distribution.
Step-by-step explanation:
Let X be a random variable that represents the speed of the drivers.
Given: population mean : M = 72 miles ,
Standard deviation: s= 3.2 miles
The probability that the drivers are traveling between 70 and 80 miles per hour based on this distribution:
![P(70\leq X\leq 80)=P(\frac{70-72}{3.2}\leq \frac{X-M}{s}\leq\frac{80-72}{3.2})\\\\= P(-0.625\leq Z\leq 2.5)\ \ \ \ \ [Z=\frac{X-M}{s}]\\\\=P(Z\leq2.5)-P(Z\leq -0.625)\\\\\\ =0.9938-0.2660\ \ \ [\text{Using p-value calculator}]\\\\=0.7278](https://tex.z-dn.net/?f=P%2870%5Cleq%20X%5Cleq%2080%29%3DP%28%5Cfrac%7B70-72%7D%7B3.2%7D%5Cleq%20%5Cfrac%7BX-M%7D%7Bs%7D%5Cleq%5Cfrac%7B80-72%7D%7B3.2%7D%29%5C%5C%5C%5C%3D%20P%28-0.625%5Cleq%20Z%5Cleq%202.5%29%5C%20%5C%20%5C%20%5C%20%5C%20%5BZ%3D%5Cfrac%7BX-M%7D%7Bs%7D%5D%5C%5C%5C%5C%3DP%28Z%5Cleq2.5%29-P%28Z%5Cleq%20-0.625%29%5C%5C%5C%5C%5C%5C%20%3D0.9938-0.2660%5C%20%5C%20%5C%20%5B%5Ctext%7BUsing%20p-value%20calculator%7D%5D%5C%5C%5C%5C%3D0.7278)
Hence, 72.78% of the drivers are traveling between 70 and 80 miles per hour based on this distribution.
Answer:
(4x3-6x) + (8x-12)= 2x
(4x3+8x) + (-6x2-12)= 2(2x-3) (x^2+2)
Step-by-step explanation:
All you have to do is simplify.
Your equation would be 2x - 12 + 3x - 15 = 23
Combine like terms and solve for x