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yKpoI14uk [10]
3 years ago
10

Formula for the surface area of a cylinder, SA = 2ar2 + 2arh. Solve for h.

Mathematics
1 answer:
MakcuM [25]3 years ago
8 0

Answer:

h=\frac{SA-2\pi r^2}{2\pi r}

Step-by-step explanation:

The formula for the surface area of a cylinder is:

SA=2\pi r^2+2\pi rh

And we want to solve for the height h.

First, subtract 2\pi r^2 from both sides. This yields:

2\pi rh=SA-2\pi r^2

Now, divide both sides by 2\pi r. This yields:

h=\frac{SA-2\pi r^2}{2\pi r}

And we're done!

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Answer:

B and E

Step-by-step explanation:

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2 years ago
In the picture below, what is the approximate area that is shaded blue?
Iteru [2.4K]

I think it’s C sorry if I’m wrong

7 0
3 years ago
A glass paperweight has a composite shape: a square pyramid fitting exacty on top of an 8 centimeter cube. The pyramid has a hei
ArbitrLikvidat [17]

Answer:

Part 1) The volume of the paperweight is 576\ cm^{3}

Part 2) The total surface area of the paperweight is 400\ cm^{2}

Step-by-step explanation:

Part 1) what is the volume of the paperweight?

we know that

The volume of the paperweight is equal to the volume of the square pyramid plus the volume of the cube

step 1

Find the volume of the pyramid

The volume of the pyramid is equal to

V=\frac{1}{3}BH

where

B is the area of the square base

H is the height of the pyramid

B=8^{2}=64\ cm^{2}

H=3\ cm

substitute

V=\frac{1}{3}(64)(3)=64\ cm^{3}

step 2

Find the volume of the cube

The volume of the cube is equal to

V=b^{3}

V=8^{3}=512\ cm^{3}

step 3

Find the volume of the paperweight

64\ cm^{3}+512\ cm^{3}=576\ cm^{3}

Part 2) what is the total surface area of the paperweight?​

we know that

The total surface area of the paperweight is equal to the surface area of 5 faces of the cube plus the lateral area of the pyramid

step 1

Find the surface area of 5 faces of the cube

SA=5b^{2}

SA=5(8^{2})=320\ cm^{2}

step 2

Find the lateral area of the pyramid

LA=4[\frac{1}{2}bh]

LA=4[\frac{1}{2}(8)(5)]=80\ cm^{2}

step 3

Find the total surface area of the paperweight

320\ cm^{2}+80\ cm^{2}=400\ cm^{2}

8 0
3 years ago
Help me please !!!!!!!!!!!!!!
tensa zangetsu [6.8K]

Answer:

\large\boxed{V=\dfrac{49\pi}{3}\ in^3}\approx51.29\ in^3}

Step-by-step explanation:

The formula of a volume of a cone:

V=\dfrac{1}{3}\pi r^2H

r - radius

H - height

We have

r = (7 : 2) in = 3.5 in

H = 4 in

Substitute:

V=\dfrac{1}{3}\pi(3.5)^2(4)=\dfrac{1}{3}\pi(12.25)(4)=\dfrac{49\pi}{3}\ in^3

\pi\approx3.14\\\\V\approx\dfrac{(49)(3.14)}{3}\approx51.29\ in^3

5 0
3 years ago
Does Anyone have idea how to solve this problem?
garik1379 [7]
A.

5 * 2 = 10

8 * 2 = 16

10 cm by 16 cm is the new dimensions. Area = 160 sq cm. Perimeter = 52 cm.

B.

5 * 3 = 15

8 * 3 = 24

15 cm by 24 cm is the new dimensions. Area = 360 sq cm. Perimeter = 78 cm.

C.

The areas for the different sized photos both still maintain a ratio of 5:8 cm.
6 0
3 years ago
Read 2 more answers
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