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2 years ago

5

Mr.Jamison brought 15 tubs of paint for the art classes he teaches for his Elementary kids. He paid $63.90 for the paint.If each

tube of paint costs the same amount, what was the price of one tube?

1 answer:

xeze [42]2 years ago

6 0

Answer:

$4.26

Step-by-step explanation:

63.90 divide by 15 = $4.26

the price of one tube is $4.26

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For which function does f decrease by 15% every time x increases by 1

LenaWriter [7]

Answer:

$f(x) = 0.85^{x}$

Step-by-step explanation:

The exponential function that decrease by 15% every time x increases by 1 is given by:

$f(x) = {(1 - 0.15)}^{x}$

We simplify the parenthesis to get:

$f(x) = 0.85^{x}$

Therefore the decrease by 15% every time x increases by 1 is

$f(x) = {0.85}^{x}$

The second choice is correct.

7 0

3 years ago

Find the area of the region enclosed by the graphs of the functions

Vaselesa [24]

Answer:

$\displaystyle A = \frac{8}{21}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

Terms/Coefficients
Functions
Function Notation
Graphing
Solving systems of equations

<u>Calculus</u>

Area - Integrals

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

*Note:

<em>Remember that for the Area of a Region, it is top function minus bottom function.</em>

<u />

<u>Step 1: Define</u>

f(x) = x²

g(x) = x⁶

Bounded (Partitioned) by x-axis

<u>Step 2: Identify Bounds of Integration</u>

<em>Find where the functions intersect (x-values) to determine the bounds of integration.</em>

Simply graph the functions to see where the functions intersect (See Graph Attachment).

Interval: [-1, 1]

Lower bound: -1

Upper Bound: 1

<u>Step 3: Find Area of Region</u>

<em>Integration</em>

Substitute in variables [Area of a Region Formula]: $\displaystyle A = \int\limits^1_{-1} {[x^2 - x^6]} \, dx$
[Area] Rewrite [Integration Property - Subtraction]: $\displaystyle A = \int\limits^1_{-1} {x^2} \, dx - \int\limits^1_{-1} {x^6} \, dx$
[Area] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle A = \frac{x^3}{3} \bigg| \limit^1_{-1} - \frac{x^7}{7} \bigg| \limit^1_{-1}$
[Area] Evaluate [Integration Rule - FTC 1]: $\displaystyle A = \frac{2}{3} - \frac{2}{7}$
[Area] Subtract: $\displaystyle A = \frac{8}{21}$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Area Under the Curve - Area of a Region (Integration)

Book: College Calculus 10e

6 0

3 years ago

ME AJUDEM PFV!!O valor da expressão (NA FOTO)simplificada é:

koban [17]

D) 16.

Espero que esto ayude hermano.

7 0

3 years ago

If the circumference of a circle measures 5 pie cm, what is the area of the circle in terms of pie?

saw5 [17]

Answer:

6.25π cm²

Step-by-step explanation:

pi = π

Circumference = 5πcm

Now first we should find radius(r)

2πr = 5π cm

pie will be cancelled and we get here

r = 5/ 2 cm

Therefore r = 2.5 cm

Now

Area (A) = πr²

= π * 2.5²

= 6.25π cm²

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3 years ago

Regular hexagon ABCDEF is inscribed in circle O. Find the measure of each arc and angle.

inessss [21]

Answer:

Measurement of angle ABC: 120

Measurement of arc ACE: 240

Measurement of arc AB: 60

Step-by-step explanation:

I got it right on my test

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2 years ago